How Can You Derive the Kinematic Equation V2x^2 = V1x^2 + 2ax(delta)x?

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SUMMARY

The discussion focuses on deriving the kinematic equation V2x^2 = V1x^2 + 2ax(delta)x using the equations V2x = V1x + ax(delta)t and (delta)x = V1x(delta)t + 1/2ax(delta)t^2. The solution involves solving for time in the first equation and substituting it into the second to eliminate time, leading to the desired equation without the delta t term. The participants emphasize that the x-components are unnecessary, as these are standard one-dimensional accelerated motion formulas from high school physics.

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The Problem:
Using V2x=V1x+ax(deltat)t and (delta)x=V1x(delta)t + 1/2ax(delta)t^2 derive the formula V2x^2=V1x^2+2ax(delta)t


Homework Equations


1st and 3rd x-component Kinematics Equations


The Attempt at a Solution


Ok, so I attempted to solve it, but it didn't work. I don't want the answer but could someone just push me in the right direction.
 
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Solve the v2x = equation for time. Substitute that expression into the other equation to eliminate time. Simplify. You will find that
V2x^2=V1x^2+2ax(delta)t
will not have the delta t at the end.

By the way, much easier if you leave out all those x's. These are just the one dimensional accelerated motion formulas from grade 11:
V = Vi + at and d = Vi*t + 0.5*a*t^2
and the one you are looking for is V^2 - Vi^2 = 2*a*d
 

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