How Can You Narrow Possibilities When Measuring Inductor Back EMF?

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Discussion Overview

The discussion revolves around measuring the back electromotive force (EMF) produced by an inductor when a switch is opened. Participants explore methods to narrow down the possibilities of predicting the voltage generated in this scenario, considering various factors that influence the measurement.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant suggests simulating the circuit using LTSpice to better understand the behavior of the inductor when the switch is opened.
  • Another participant proposes that leaving the switch open for a short period before closing it may simplify the prediction of back EMF, but notes that this approach results in zero back EMF at that moment.
  • A later reply discusses the complexities involved when opening a switch in series with an inductor, mentioning factors such as switch bounce and potential arcing if the voltage rises too high.
  • Some participants highlight that the inductor's current cannot change instantaneously, referencing the equation V = L*dI/dt to explain that a sudden change in current leads to a large voltage generation.
  • One participant outlines various scenarios affecting the instantaneous voltage of the inductor after the switch is turned off, emphasizing that the loading impedance (Za) plays a crucial role in determining the back EMF.
  • Examples are provided indicating that the back EMF can vary significantly based on the nature of the loading impedance, with different outcomes depending on whether Za is a high resistance, another inductor, or a capacitor.
  • There is a consensus that using simulation tools is generally more effective for predicting circuit behavior than manual analysis.

Areas of Agreement / Disagreement

Participants express a range of views on the predictability of back EMF, with some agreeing on the utility of simulations while others discuss the complexities and uncertainties involved in real measurements. No consensus is reached on a definitive method for narrowing possibilities.

Contextual Notes

Participants acknowledge limitations in predicting back EMF due to factors like switch bounce, arcing, and the nature of the loading impedance. The discussion highlights the dependence on specific circuit conditions and the complexity of the inductor's behavior.

David lopez
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i am planning to measure the back emf produced by inductor when you open a switch. i know it is very hard to predict the voltage. but is there any
way to narrow the possibilities?
 
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Try to simulate the circuit first with something like (free) LTSpice.
 
i am thinking i will leave the switch open for a short period of time. then i will close the switch. is the back emf easy to predict then?
 
David lopez said:
i am thinking i will leave the switch open for a short period of time. then i will close the switch. is the back emf easy to predict then?
Yeah, it's zero when you do that, so much easier. 😉

For the case of opening a switch in series with an inductor, many things come into play. There is switch bounce (what kind of switch?), and if the voltage can rise high enough, you have to account for arcing.

A better approach is to use a semiconductor switch to eliminate bouncing, and use a small capacitance to give you a predictable peak voltage from the back EMF. That's how flyback transformer circuits for CRTs work, for example.
 
David lopez said:
i am planning to measure the back emf produced by inductor when you open a switch. i know it is very hard to predict the voltage. but is there any
way to narrow the possibilities?

In principle, current of inductor cannot be changed instantaneously.

The inductor equation V = L*dI/dt means that if the current changes suddenly, a very large voltage will be generated.

This means that after the switch is turned off, the inductor current will try hard to flow continuously at the same amplitude.

In short, let Ia be the current just before turning off the switch, then the instantaneous voltage of the inductor just after turning off the switch is equal to Ia multiplied by Za (loading Impedance).

Namely Va = Ia * Za, where Va is instantaneous voltage of the inductor just after the switch is turned off.

Prediction Examples : -
Va will be very large if Za is a very high resistance
Va will be extremely large if Za is another high inductance inductor with zero initial current
Va will be nearly zero if Za is a high capacitance capacitor with zero initial voltage
Va will be very difficult to be predicted if Za is a complex network which containing L, C , R and other power sources.
...etc

Of course, the long-term varying of the inductor voltage/current after the switch is turned off is another story.

All in all, in today's times, using simulation to predict circuit behavior is much easier than analysis.
 
Last edited:

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