How close will body approach fixed point charge?

Click For Summary
SUMMARY

The discussion centers on calculating the closest approach of a charged sphere with a mass of 15 mg and a charge of 2 nC towards a fixed point charge of 3 nC. The initial kinetic energy is calculated using the formula K=(1/2)*mv², resulting in an energy of 1.6875 x 10^-4 Joules. By equating the initial energy to the final potential energy U=k*(Q1Q2/r), the distance of closest approach can be determined. The approach is confirmed to be correct, ensuring that energy conservation principles are applied accurately.

PREREQUISITES
  • Understanding of electrostatics, specifically Coulomb's law.
  • Familiarity with kinetic and potential energy equations.
  • Knowledge of energy conservation principles in physics.
  • Basic proficiency in algebra for solving equations.
NEXT STEPS
  • Study Coulomb's law and its applications in electrostatics.
  • Learn about energy conservation in electric fields.
  • Explore the concept of electric potential energy in detail.
  • Practice solving problems involving charged particles and their interactions.
USEFUL FOR

Students in physics, particularly those studying electrostatics, as well as educators looking for problem-solving examples related to charged particles and energy conservation.

Aleksandre
Messages
11
Reaction score
0

Homework Statement


Charged sphere with a mass of 15 mg and charge 2 nC moves with a speed of 15 cm/s towards a fixed point charge of 3 nC. How close will sphere approach charge?

Homework Equations


K=(1/2)*mv2
U=k*(Q1Q2/r)

The Attempt at a Solution



So I am not sure I approached correctly but that's all I could think of. As system initial energy = final energy I used formulae of kinetic energy and potential energy. At first, I assumed that initial distance was infinity. In that case, the initial energy in system would be expressed as :

Einitial=(1/2)*(mv2) = 1.6875 * 10-4 Joules

Then when the sphere reached to the point where electric field vector of point charge was so big that it had to stop, sphere stopped so v=0. That brings us to the Efinal equation:

Efinal=U=kQ1Q2/x
Here everything is known except x. So if we equate this equation to Einital we can find x distance easily. Also as units work out, I think this may be correct solution?
 
Physics news on Phys.org
Aleksandre said:
I think this may be correct solution?
It is.
 
  • Like
Likes Aleksandre

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
8
Views
3K