1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Velocity of a particle kicked into four point charge square

  1. Jul 18, 2017 #1
    1. The problem statement, all variables and given/known data
    Consider the arrangment of charges (fixed in place) shown in the figure. The square has side length d. (Figure 1)

    Now suppose the particle with charge q is released. It is "kicked" so that it's initial speed is v. After an unspecified trajectory, it is observed that the particle ends up at the center of the original square and is momentarily at rest. If the mass of this particle is m, what was its initial speed v?
    Express your answer in terms of q, d, m, and appropriate constants. Use k instead of 14πϵ0. The numeric coefficient should be a decimal with three significant figures.

    2. Relevant equations
    U = kq1q2/r
    KE = 1/2mv^2

    3. The attempt at a solution
    So I know I have to find the initial and final U of each total charge on a charge q. The problem is how does one do that besides doing kQ1q2/d + kQ3q4/d...etc? I would just add all of the contributions right? The little q would stay little q, but big Q would be the charge of each of the four point charges. Then I have to find final Potential Energy, but what would that even be? 0? Then I know that I have to use kinetic energy since I have to use the law of conservation of energy. I am confused on what I need to do from here since I can't figure out the potential energies. I know I will have this in the end KEi + Ui = KEf + Uf where KEf is zero. Thanks for any help!
     

    Attached Files:

  2. jcsd
  3. Jul 18, 2017 #2

    kuruman

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    The best way to do this problem is
    1. Pretend that the charge q that is kicked is not there.
    2. Find the electric potential Vi at the corner where the charge is.
    3. Find the electric potential Vf at the center of the square where the charge ends up.
    4. Conserve energy where PEi = q Vi and PEf = q Vf, KEi = ½mv2 and KEf = 0.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Velocity of a particle kicked into four point charge square
  1. Four Point Charges (Replies: 3)

Loading...