How Deep Can a Snorkeler Dive with a 1/20 Atmosphere Lung Pressure Difference?

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Homework Help Overview

The problem involves determining the maximum depth a snorkeler can dive based on a specified pressure difference in the lungs while submerged in salt water. The subject area includes fluid mechanics and pressure calculations related to diving physics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the pressure inside the lungs and the external water pressure, with one participant attempting to set up an equation involving gauge pressure. Questions arise regarding the correct interpretation of the pressure values and how to apply them in the context of the problem.

Discussion Status

The discussion is ongoing, with various interpretations of the pressure dynamics being explored. Some participants express uncertainty about the calculations and seek further suggestions or alternative approaches.

Contextual Notes

There is a mention of the specific density of salt water and the pressure difference constraint, but no consensus has been reached on the correct method to solve the problem. Participants are navigating through assumptions about the pressures involved.

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Homework Statement


The human lungs can function satisfactorily up to a limit where the pressure difference between the outside and inside of the lungs is 1/20 of an atmosphere. If a diver uses a snorkel for breathing, how far below the water can she swim? Assume the diver is in salt water whose density is 1029 kg/m3.


Homework Equations


1 atm = 1.013e5 Pa
1/20 atm = 5065 Pa
P1 + P2 = gauge pressure
P = density*gravity*height
P = Force/Area

The Attempt at a Solution



So the pressure in the lungs minus the pressure outside the lungs must be less than 5065 Pa. If
P1-P2 = 5065 and
P2 = 1029*height
these should just be combined somehow. However, how do I know what the pressure is inside the lungs? If I use 1 atm,
1.013e5 - 1029(g)(h) = 5065
96235 = 1029(9.8)(h)
h = 9.54 m
But this is not correct. Does anyone have a suggestion?
 
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I would expect the pressure under water to be greater so I'd take the under water pressure away from the pressure in the lungs. The difference is not that great however.
 
Ok so any other ideas?
 
I came up with about 0.5 meters.
 

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