Pressure and density in swimming.

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SUMMARY

The discussion centers on calculating the maximum depth a diver can swim using a snorkel, given a pressure difference limit of 1/21 of an atmosphere and the density of salt water at 1042 kg/m³. The pressure difference converts to 4824 Pascals. The relevant equation for this calculation is pgh, where p is the water density, g is the gravitational acceleration (approximately 9.81 m/s²), and h is the height or depth. By rearranging the equation to solve for h, the maximum depth can be determined.

PREREQUISITES
  • Understanding of fluid mechanics principles
  • Knowledge of pressure conversion (atmospheres to Pascals)
  • Familiarity with the equation of hydrostatic pressure (pgh)
  • Basic grasp of gravitational acceleration (9.81 m/s²)
NEXT STEPS
  • Calculate maximum depth using the formula h = P / (ρg) with P as 4824 Pascals, ρ as 1042 kg/m³, and g as 9.81 m/s².
  • Explore the effects of varying water densities on diving depth limits.
  • Research the physiological impacts of pressure changes on human lungs during diving.
  • Learn about the design and function of snorkels in relation to pressure and breathing underwater.
USEFUL FOR

Students studying physics, diving instructors, marine biologists, and anyone interested in the effects of pressure and density on underwater activities.

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Homework Statement


The human lungs can function satisfactorily up to a limit where the pressure difference between the outside and inside of the lungs is 1/21 of an atmosphere. If a diver uses a snorkel for breathing, how far below the water can she swim? Assume the diver is in salt water whose density is 1042 kg/m3.

Homework Equations


The Attempt at a Solution


I think pgh, where p is density, g is gravitational acceleration, and h would be the height. I think the height would tell you how far the swimmer could go below water. I'm honestly not exactly sure where to start this one!
 
Last edited:
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That pressure has to be equal to 1/21 atm right? Remember the units are going to be different and account for that.
 
I converted the 1/21 atm to 4824 Pascals. I am still not sure how to find the height below the water the swimmer can go though?
 

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