- #1

- 464

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## Homework Statement

X(x)=(Ae^kx+Be^-kx)

Y(y)=(Csin(ky)+D(cos(ky))

V(x,y)=(Ae^kx+Be^-kx)(Csin(ky)+D(cos(ky))

## Homework Equations

separation of variables

## The Attempt at a Solution

so our boundary condition says that as x->infinity , V=0

this is only possible if A=0

so A=0 and Be^-kx= 0

so X= Be^-kx

and

V(x,y)=(e^-kx)(Csin(ky)+D(cos(ky))

why is there an e^-kx on the front. Shouldn't there also be a B?