How do contact forces affect collisions and object launches?

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SUMMARY

This discussion focuses on the application of contact forces in collisions and object launches, specifically analyzing a scenario involving a girl on frictionless rollers launching a ball. The key takeaway is that when a force is applied, such as the girl pushing against a wall, the resulting motion can be calculated using the principles of conservation of momentum and energy. The discussion emphasizes the importance of understanding elastic and inelastic collisions, as well as the concept of impulse, which is defined as the change in momentum resulting from a force applied over time.

PREREQUISITES
  • Understanding of Newton's Third Law of Motion
  • Familiarity with elastic and inelastic collisions
  • Knowledge of conservation of momentum and energy principles
  • Basic grasp of impulse and its calculation
NEXT STEPS
  • Study the equations governing elastic and inelastic collisions on Hyperphysics
  • Learn how to calculate impulse and its effects on momentum
  • Explore examples of contact forces in real-world applications
  • Investigate the relationship between work done and kinetic energy in launching objects
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of collisions and object launches, particularly in scenarios involving contact forces and momentum conservation.

alba
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I have recently studied collisions, in which one or two bodies are already in motion.
I have tried to apply them to cases in which the bodies are initially at rest, like launching or kicking a ball etc, but they do not work.
Can you tell me how to google to find them, 'contact force' gives everything, I tried 'explosive forces' but I get only explosives.
Can you help me?:
suppose a girl (20 kg) on frictionless rollers launches a ball (1kg) doing work 210 J, what is the rule to find the outcome?

I imagine that if she pushes at a wall the outcome is the same of an elastic collision with a wall of a body of 20kg, , if so, she will move backward at v = √210*2/20 = - 4.58 m/s. Is that right?

Is the force on the wall equal to the force that acts on the girl? and what about momentum? the girl's is -91.6 kgm/s the wall's should be the same, but in that case it would mean it subtracted energy to the girl and her speed will be less?
How do I deal with the ball? do you have a link or a formula?
Thanks
 
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If you can already 'do' objects in motion then why not just put the initial velocity of one of them to zero? If you are not getting the right answer, it could be that you are not doing the right sum. Have you looked at the Hyperphysics pages on Elastic and Inelastic Collisions? All the relevant equations and ideas are presented there, although you have to learn to drive their system to get the most out of it.

The way to solve specific problems will depend upon what you are given. If the collision can be assumed to be elastic then no energy is 'lost' and you can use conservation of Energy. If not, you can always rely on Momentum being conserved. Newton 3 always applies, of course.
Have you come across the quantity 'Impulse'? That is the Change in Momentum and is given by the Force times the Time it's applied.
 

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