How Do Degree Odd Polynomials Relate to Extension Fields of K?

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SUMMARY

The discussion focuses on the relationship between degree odd polynomials and extension fields of K, specifically examining the inclusion of fields K(a^2) in K(a) and the implications of the minimal polynomial's degree. It is established that if F is an extension field of K and a is algebraic over K with an odd degree minimal polynomial m(x), then K(u) equals K(a^2). The participants explore the use of field degree relationships to derive these conclusions, emphasizing the significance of the polynomial's degree in determining field equality.

PREREQUISITES
  • Understanding of extension fields and their properties
  • Knowledge of algebraic elements and minimal polynomials
  • Familiarity with field degree notation and relationships
  • Concept of odd-degree polynomials in field theory
NEXT STEPS
  • Study the properties of extension fields in algebraic structures
  • Learn about minimal polynomials and their role in field extensions
  • Research the implications of odd-degree polynomials in algebra
  • Explore theorems related to field degree relationships, such as the Tower Law
USEFUL FOR

This discussion is beneficial for mathematicians, algebraists, and students studying field theory, particularly those interested in the properties of extension fields and polynomial degrees.

kathrynag
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1.Let F be an extension field of K and let u be in F. Show that K(a^2)contained in K(a) and [K(u):K(a^2)]=1 or 2.

2.Let F be an extension field of K and let a be in F be algebraic over K with minimal polynomial m(x). Show that if degm(x) is odd then K(u)=K(a^2).



1. I was thinking of doing something like [K(u):K(a)][K(a):K(a^2)]

2. algebraic so there exists a polynomial m(x) such that m(a)=0.
Just not sure how to work in the degree being odd.
 
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Is this a good way to start or should I try something different?
 
2. I was thinking of somehow using a theorem stating [F:K]=[F:K(u)][K(u):K]
based on the deg m(x) being odd, I would say deg m(x)=2n+1
 

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