How Do Factors Relate in the Quadratic Form N^2 - 3N + 1?

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The discussion centers on the quadratic form F_{n} = n^{2}-3n+1 and its factorization properties. It establishes a relationship involving factors p_n and their quotients p_{n}^{'} through the equation \(\frac{F_{n}}{p} * \frac{F_{(n+p)}}{p} = F_{(n+p_{n}^{'})}\). A specific example demonstrates this relationship by letting p = 1, leading to the equation \(F_{n} * F_{(n+1)} = F_{(n+F_{n})}\). The conversation highlights the broader applicability of this relationship to any monic quadratic polynomial with integer coefficients.

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ramsey2879
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I noted the following relation for the form [tex]F_{n} = n^{2}-3n+1[/tex]
let [tex]p_n[/tex] be any whole factor of [tex]F_n[/tex] and [tex]p_{n}^{'}[/tex] be the quotient. The following relation then holds

[tex]\frac{F_{n}}{p} * \frac{F_{(n+p)}}{p} = F_{(n+p_{n}^{'})}<br /> <br /> A trivial example would be to let p = 1. Then<br /> [tex]F_{n} * F_{(n+1)} = F_{(n+F_{n})} <br /> <br /> Is this something that is of interest?[/tex][/tex]
 
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You could at least put closing /tex's in. It is common to let quotients be q's and i notice that the subscript n's vanish in your (non-closed off) latex, should they?
 
I think you're saying something equivalent to: f(n)=n^2-3*n+1, and if f(n)=a*b for some n, then f(n+a)/a=f(n+b)/b. This is actually true for any monic quadradic polynomial with integer coefficients.
 

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