How Do Final Speeds of Two Balls Compare When Thrown from a Building?

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SUMMARY

The discussion analyzes the final speeds of two balls thrown from a building: one thrown upward and the other downward, both with an initial speed of vi. The final speed of ball 1, v1f, is equal to the final speed of ball 2, v2f, upon reaching the ground, demonstrating that both balls experience the same gravitational acceleration. The equations of motion, specifically vf = vi + a(delta t), confirm that the upward trajectory of ball 1 results in a return to the original speed before descending, while ball 2 accelerates downward. Thus, v1f = v2f, establishing a direct relationship between their final speeds.

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Homework Statement


A student at the top of a building of height h throws ball 1 upward with a speed of vi and then throws ball 2 downward with the same initial speed, vi. How does the final speed of ball 1, v1f, compare to the final speed of ball 2, v2f, when they reach the ground?
v1f = ______ multiplied by v2f

Homework Equations


a = delta v/delta t
vf = vi + a(delta t)

The Attempt at a Solution


I drew a picture showing the person throwing ball 1 upward and then it descending and ball two falling to the ground.
 
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Okay well let's think about this. We know if there is presence of uniform force in only one dimension then the trajectory is going to be parabolic. For ball 1, it will leave his hand at vi go up in its arc, reach a maximum height (where vertical velocity is zero) begin to fall again with identical acceleration as before.
This implies that when it passes the thrower for, it will have the same velocity it was thrown with, but in the opposite direction.
 

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