How do find out gravitational pull according to GR?

[jinchuriki300]

we know that on Earth, an object falling with a rate of g horizontally, and the formula for it is
a=g*cos x. So according to GR, an object falls into the warp of space time that a huge object causes. So should there be a new "g" applied to all the warp in space time? Am i right or not?

 

[HallsofIvy]

In general relativity, the motion of objects under gravity depends upon the geodesics defined by the metric tensor which itself is determined by the curvature tensor, not by a force so there is no equation like "g cos(theta)". In practice, of course, Newton's theory is a good approximation.