How Do Forces Affect the Motion of a Doughnut?

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SUMMARY

The discussion centers on calculating the net force and acceleration of a doughnut being pulled by three forces: Ted's 5.0N eastward, Ahmad's 4.0N northward, and Alysha's 6.0N northwest. The net force is determined to be 8.3N at an angle of 5.2 degrees east of north. The acceleration of the doughnut, given its mass of 0.125g, is calculated to be 66m/s² in the same direction as the net force. The angle is derived using trigonometric functions to resolve the vector components along the x and y axes.

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Question:
Ted pulls a 0.125g doughnut with force 5.0N[E], Ahmad pulls with a force of 4.0N[N], and Alysha pulls with a force of 6.0N[NW].

Find the net force on the doughnut and find the acceleration of the wagon.

Answers: 8.3N[N 5.2* E], 66m/s^2 [N5.2*E]

Ok.. so I am not sure how to get the answers and especially the 5.2 degrees..
I am guessing that the "NW" stated in the question is.. to say 45degrees? Bleh, please help.
 
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NW means 45 degrees.
Now resolve the vector pointing NW along x and y axis.
Then find net x and y components and then the resultant.
The angle between resultant and the x-axis is given by
tanθ = Net Fy/Net Fx
 

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