I How do I calculate brake force for an eddy current brake?

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To calculate brake force for an eddy current brake, determining the frequency and characteristic length is crucial, specifically the skin depth and magnetic Reynolds number. The discussion includes shared equations and a model scheme to aid in the calculations. Participants are encouraged to refer to the linked thread for additional insights and references. Understanding these parameters is essential for accurate brake force calculations. The conversation focuses on the technical aspects of modeling eddy current brakes effectively.
Paul1999
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I try to calculate brake force for primitive eddy current brake, but I have problem with determining the frequency (skin depth) and characteristic length (magnetic Reynolds number)
Hello everyone, I try to calculate brake force for primitive eddy current brake, but I have problem with determining the frequency (skin depth) and characteristic length (magnetic Reynolds number). I attach the equations and a scheme of the model.

1.png


Scheme.png
 
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Thread 'Why higher speeds need more power if backward force is the same?'

Thread 'Why higher speeds need more power if backward force is the same?'

Power = Force v Speed Power of my horse = 104kgx9.81m/s^2 x 0.732m/s = 1HP =746W Force/tension in rope stay the same if horse run at 0.73m/s or at 15m/s, so why then horse need to be more powerfull to pull at higher speed even if backward force at him(rope tension) stay the same? I understand that if I increase weight, it is hrader for horse to pull at higher speed because now is backward force increased, but don't understand why is harder to pull at higher speed if weight(backward force)...
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