How do I calculate heat lost by the hot water in a calorimeter?

[blicker]

Homework Statement

1. Calculate heat lost by the hot water in the calorimeter.
Initial temp: 22.90 C
Finial temp: 23.25 C
Density: 1.00 g/mL
specific heat capacity: 4.18 J/gK

Homework Equations

qmetal=-(qwater+qmetal)

q=m C dT

The Attempt at a Solution

When i use the second equation i end up stuck.
=(mass of water)(4.18)(23.25-22.90)

but he didnt give us a mass he gave us density. So i think I am supposed to use the first eqauation, but i don't know where to start with that one. how would i solve this problem with the first equation? Or are the two equations basically the same thing?

 

[Borek]

Just density is not enough.

Is it all information you were given?

 

[blicker]

yes that's all he gave us. ill have to ask him about that question.
another question i have is how to calculate the heat gained by the water in the calorimeter after adding the aluminum.

this is what he gave us:
temp of water in calorimeter before adding metal: 22.90 C
mass of test tube: 32.679 g
mass of aluminum: 50.155 g
temp of aluminum: 100 C
temp of aluminum and water 32.19 C
temp of water in calorimeter after adding metal: 23.25 C

 

[Borek]

temp of water in calorimeter before adding metal: 22.90 C
mass of test tube: 32.679 g
mass of aluminum: 50.155 g
temp of aluminum: 100 C
temp of aluminum and water 32.19 C
temp of water in calorimeter after adding metal: 23.25 C

Not knowing procedure that was followed I have no idea what is what of what.

Perhaps this is a series of questions and they are somehow related - that is, answer from earlier question can be used as input in the next one?

 

[blicker]

no this is a separte question from the first one i asked.