How do I calculate the impulse delivered by a pipe bending machine?

[Eagle Eyes]

A pipe bending machine applies a force (in Newtons) given by F(t) - 19.2t - 3t^2, where t is in seconds. The impulse delivered to a pipe during the interval t =0 to 6.4 sec equals..

The answer is 131 N-s. But why.. can somebody explain it step by step. URGENT help required.

Thanks a lot.

 

[mrandersdk]

look here:

http://en.wikipedia.org/wiki/Impulse

you need to calculate the integral

$$\int _0^{6.4} 19.2 t - 3t^2 dt$$

asuming you ment F(t) = 19.2 t - 3t^2 , not F(t) - 19.2 t - 3t^2.