How do I calculate the joint distribution for N events?

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Discussion Overview

The discussion revolves around calculating the joint distribution for N random events originating from two different sources, one following a binomial distribution and the other a Poisson distribution. Participants explore how to determine the probability of observing N events given the parameters of both distributions.

Discussion Character

  • Exploratory
  • Mathematical reasoning

Main Points Raised

  • One participant describes a scenario involving N random events from two sources, questioning how to calculate the probability of observing these events given the distributions.
  • Another participant suggests that the solution involves summing the probabilities of all possible combinations of events from both distributions.
  • A clarification is made regarding the interpretation of the events as independent random variables, leading to a proposed formula for calculating the probability of observing a specific number of events.
  • Participants discuss the specific case of measuring 3 events and outline a formula based on the probabilities from both distributions.

Areas of Agreement / Disagreement

There is no clear consensus on the exact method for calculating the joint distribution, as participants express uncertainty and explore different interpretations of the problem.

Contextual Notes

Participants note the ambiguity in the initial problem statement, which may affect the clarity of the proposed solutions. The discussion does not resolve the mathematical steps involved in the calculations.

Quaoar
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Hi,

I have a situation where there are N random events. These events can be from either one of two sources, one with a binomial distribution, the other with a Poisson distribution. The events do not provide any evidence of their origin, either distribution could be responsible for creating the event.

The question is, how do I calculate the probability that there will be N events given the parameters for both distributions?
 
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Your statement of the problem is a little unclear. But I suspect the answer is "add up the odds of all possible ways it could happen".
 
Hurkyl said:
Your statement of the problem is a little unclear. But I suspect the answer is "add up the odds of all possible ways it could happen".

Well, basically each distribution pops out a random number of events, and these events are then observed as a total number of events. Looking at a particular event, I cannot tell if it originates from the binomial or the Poisson distribution.

So I guess what you're saying is, the probability of measuring say, 3 events, is:

P_1(0) * P_2(3) + P_1(1) * P_2(2) + P_1(2) * P_2(1) + P_1(3) * P_2(0)

Correct?
 
Well, basically each distribution pops out a random number of events, and these events are then observed as a total number of events.
In other words, you're just looking at the sum of two independent random variables?


So I guess what you're saying is, the probability of measuring say, 3 events, is:

P_1(0) * P_2(3) + P_1(1) * P_2(2) + P_1(2) * P_2(1) + P_1(3) * P_2(0)
Sounds reasonable.
 

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