How do I calculate the rate of water being pumped into an inverted conical tank?

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SUMMARY

The discussion focuses on calculating the rate at which water is being pumped into an inverted conical tank, given specific parameters. The tank has a height of 6 meters and a top radius of 2 meters, with water leaking at a rate of 0.01 m³/min. The water level is rising at 0.2 m/min when the height of the water is 2 meters. To solve the problem, participants suggest using the formula for the volume of a cone and applying the concept of similar triangles to relate the height and radius of the water in the tank.

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rkennedy9064
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I need help understanding a problem for my homework assignment. I'm not sure how to set up the problem. If anyone could help I would greatly appreciate it.

Homework Statement


Water is being pumped into an inverted conical tank at a constant rate. However, water is also leaking out of the tank at a constant rate of 0.01m^3/min. The tank is 6m tall and the radius at the top of the tank is 2 m. If the water level is rising at a rate of 0.2m/min at the moment when the height of the water is 2m, find the rate at which water is being pumped into the tank.


Homework Equations



The Attempt at a Solution



I know I need to find the rate of change, but I'm not sure how exactly I set up this problem.
 
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welcome to pf!

hi rkennedy9064! welcome to pf! :wink:

call the height of the water y(t), the volume of water w(y), and the pumping rate p

then write an equation for dw/dt …

what do you get? :smile:
 
Do you know the formula for the volume of a cone with height h and base radius r?

You will want to reduce from two variables, h and r, to only one- either h or r. You can do that by seeing that for the entire tank r= 2 while h= 6 and the cone formed by the water maintains that shape (think "similar triangles").
 

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