Water is leaking out of an inverted conical tank at a rate of 6500 cm3/min at the same time that water is being pumped into the tank at a constant rate. The tank has height 6 m and the diameter at the top is 4 m. If the water level is rising at a rate of 20 cm/min when the height of the water is 2 m, find the rate at which water is being pumped into the tank.
Substituting h for r:
V=1/3 pi (1/3h)^2(h)
V'=dv/dt= pi/27 (3h)^2dh/dt
since the cone is leaking we have to find: