How do I calculate the work done by melting ice?

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SUMMARY

The discussion focuses on calculating the work done during the melting of ice, specifically 1 kilomole of ice at 0°C. The latent heat of fusion for ice is given as 3.348 x 10^5 J/kg, with the densities of ice and water at 917 kg/m³ and 999.9 kg/m³, respectively. The work done is expressed as W = P(V2 - V1), where pressure P is derived from the ideal gas law, P = nRT/V. The challenge lies in determining the volume V for the transition from ice to water at the melting point.

PREREQUISITES
  • Understanding of latent heat and its application in phase changes
  • Familiarity with the ideal gas law (PV = nRT)
  • Knowledge of density and its role in calculating volume
  • Basic principles of thermodynamics related to work and energy
NEXT STEPS
  • Calculate the volume of 1 kilomole of ice using its density (917 kg/m³)
  • Explore the relationship between pressure and volume during phase transitions
  • Investigate the implications of using the ideal gas law for solids and liquids
  • Learn about the thermodynamic properties of water and ice at 0°C
USEFUL FOR

Students and professionals in physics, chemistry, and engineering who are studying thermodynamics and phase transitions, particularly those interested in the energy calculations involved in melting processes.

cashmerelc
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Okay, if you have 1 kilomole of ice melting at 0 C and you have a given latent heat of fusion of ice as 3.348 x 10^5 J/kg and the density of ice as 917 kg/m^3 and te density of water as 999.9 kg/m^3, I don't understand how to find the work done.

I know that work done is PdV, so it should be W=P(V2-V1).

I understand that the volumes is the mass in kg of the water molecules over the densities of ice and water. But how do you solve P?

P=nRT/V. so P = (1 kilomole)(8.314 x 10^3 j/kK)(273 K)/V.

I don't really understand how to solve for V.
 
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There's only one pressure where ice melts at 0°C. You're not really trying to bring the ideal gas law into a question about a solid and a liquid, are you?
 
1 atm?
 

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