How do I calculate these questions relating to roots of quadratic equation?

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SUMMARY

The discussion focuses on solving two quadratic equations to find specific expressions involving their roots. For the equation x² + 2x - c = 0, the expression 2b - a² simplifies to -4 - c. For the equation x² - 3x + k = 0, the expression a² + 3b simplifies to 9 - k. The key techniques discussed include using the sum and product of roots to derive these expressions.

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Homework Statement


These two questions are very similar:
1) Let c be a constant. If a and b are the roots of the equation x^2 + 2x - c = 0
then 2b-a^2 = ?

2) Let k be a constant. If a and b are the roots of the equation x^2 - 3x + k = 0
Then a^2 + 3b = ?



Homework Equations


The answer to these 2 questions are -4-c and 9-k.


The Attempt at a Solution


For the first one, I was thinking about using the sum of roots and product of roots, I know that a+ b is -2 and ab must be c, but I don't know how to convert 2b-a^2 into a new equation that only consists of a+b and ab . I used another approach, which is to turn the equation into 2 separate ones by knowing the two roots given, a^2 + 2a - c = 0 and b^2 + 2b - c = 0. Then after some change of subject, I'll know that a^2 = c-2a and 2b = c-b^2 . But if I put in these two together, 2b-a^2 will equal to c-(b^2)-c+2a, which will finally give 2a-b^2, which doesn't really solve the problem...
I thought of another way, which is to let those unknowns to be a random number. Since this is a multiple choice question, I can get the answer by try and error. However, I was thinking if there's a better way.
Thanks :smile:
 
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Your first approach was right. a+b=(-2). So b=(-2)-a. 2b-a^2=2(-2-a)-a^2=(-4)-(2a+a^2). Now finish up.
 

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