How do I change the variable in this expression?

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Homework Help Overview

The discussion revolves around rewriting an expression as a single product through a change of variable. The context involves understanding how to manage different upper and lower limits in the expression.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the necessity of introducing new variables to handle the change of variable effectively. There are attempts to define relationships between variables, such as letting j = k + 1 or j = (k + 1)/(k + 2), and questions arise about the implications of these definitions on the limits of the products.

Discussion Status

Some participants express confusion regarding the approach to the problem, indicating a lack of clarity on how to properly change the variable without altering the expression itself. Guidance has been offered regarding the use of dummy variables and the need to ensure consistent limits across the products.

Contextual Notes

There is an indication that the original poster is grappling with the concept of changing variables in the context of products with differing limits, which may not have been fully addressed in their initial resources.

PolyFX
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Homework Statement


Rewrite the following expression as a single product.
Hint: Perform a change of variable first.

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Homework Equations


The Attempt at a Solution


I looked at the example from the book regarding a change of variable. They first started out by calculating the upper and lower limits of the expression. However, in this the upper limits and lower limits are different. For example, the right product expression has an upper limit of n - 1 while the left has an upper limit of n. Furthermore, I can make for example j = k+1 but then what about k+2? Would I need to introduce a new variable or do i make j = (k+1) + 1 to represent k +2?

How do I go about performing a change of variable with this expression?
 
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PolyFX said:
… Would I need to introduce a new variable or do i make j = (k+1) + 1 to represent k +2?

How do I go about performing a change of variable with this expression?

HI PolyFX! :smile:

You'll avoid mistakes if you do introduce a new variable, to go from 0 to n-1.

You can then turn that new variable back to k (it's only a "dummy" variable :wink:) in the next step.
 
Hi sorry for the late reply,

I am still somewhat confused about how to approach this question. So far this is how I've startend it.

Let j = K+1/K+2

Therefore when k = 0,
j = 1/2
and when K = n - 1,
j = (n-1) + 1 / (n-1 ) + 2
j = n


So I introduce another variable for the other product expression?

so let x = K+1/K+2
when k = 1
j=2/3
and when k = n
j = n+1/n+2

I am stuck here.


To me I get the feeling that I am definitely doing something wrong. Would be great if someone get further help me out here.


-Thank you
 
PolyFX said:
Hi sorry for the late reply,

I am still somewhat confused about how to approach this question. So far this is how I've startend it.

Let j = K+1/K+2
No! You've completely misunderstood. The point was to change the "variable" (index), not the expression itself!

The first product goes from k=0 to n-1. If we let j= k+1, it will go from j= 0+1= 0 to (n-1)+ 1= n, just like the second product.
Now, change the expression to j: since j= k+1, k= j- 1 and so k+ 1 becomes j while k+2 becomes j-1+ 2= j+1. Now you have
\left[\Pi_{j=1}^n\frac{j}{j+1}\right]\left[\Pi_{k=1}^n\frac{k+1}{k+2}\right]

Now, since the "k"s are dummy indexes, you can just let the "j" in the first product be "k" to get
\left[\Pi_{k=1}^n\frac{k}{k+1}\right]\left[\Pi_{k=1}^n\frac{k+1}{k+2}\right]
and now you can multiply those.

Therefore when k = 0,
j = 1/2
and when K = n - 1,
j = (n-1) + 1 / (n-1 ) + 2
j = n


So I introduce another variable for the other product expression?

so let x = K+1/K+2
when k = 1
j=2/3
and when k = n
j = n+1/n+2

I am stuck here.


To me I get the feeling that I am definitely doing something wrong. Would be great if someone get further help me out here.


-Thank you
 

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