How do I convert from kJ/kg to kJ/mol?

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SUMMARY

The conversion of isobutanol's heat of combustion from kJ/kg to kJ/mol involves using its molar mass of 74 g/mol. The heat of combustion is 35.981 kJ per gram, which means that burning one mole (74 grams) yields 74 times this amount. Therefore, the heat of combustion for isobutanol in kJ/mol is calculated as 35.981 kJ multiplied by 74, resulting in a total of 2665.654 kJ/mol.

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charlotteyip
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I have researched that isobutanol has a heat of combustion of 35981 kJ/kg; however I need this to be in kJ/mol. From calculations, the molar mass of isobutanol was found to be 74g/mol. How would I go about in converting this?

Relevant equations (?)
#mols=mass/molarmass

But how can I use this?
 
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74g/mol
What is the heat of combustion of one gram?

35.981 kJ per gram
You get 35.981 kJ when you burn one gram, and a mole is 74 grams.
So wouldn't burning a mole just give you 74 times as much as burning one gram?

What is 35.981 multiplied by 74?
 
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marcus said:
74g/mol
What is the heat of combustion of one gram?

35.981 kJ per gram
You get 35.981 kJ when you burn one gram, and a mole is 74 grams.
So wouldn't burning a mole just give you 74 times as much as burning one gram?

What is 35.981 multiplied by 74?
Thanks! I get it now :)
 

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