How do I convert the equation y = x^(2) to polar coordinates?

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SUMMARY

The equation y = x² can be converted to polar coordinates using the relationships x = r cos(θ) and y = r sin(θ). By substituting these into the equation, we derive r sin(θ) = (r cos(θ))², which simplifies to r sin(θ) = r² cos²(θ). To isolate r, one can divide both sides by r, yielding sin(θ) = r cos²(θ), while noting that r = 0 remains a valid solution. This conversion process is essential for understanding polar coordinate transformations in mathematics.

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  • Learn about the implications of r = 0 in polar equations
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stau40
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Homework Statement


Convert to an equation in polar coordinates y = x^(2)


Homework Equations


x = r cos (theta) , y = r sin (theta) , tan (theta) = y/x


The Attempt at a Solution


Here is my work so far: y=x^(2) so r sin (theta) = (r cos (theta))^2 and r sin (theta) = r^(2) cos^(2) theta. I'm not sure how to move the r's to one side of the equation though. Can I apply tan (theta) = y/x or ? Thanks in advance!
 
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stau40 said:

Homework Statement


Convert to an equation in polar coordinates y = x^(2)


Homework Equations


x = r cos (theta) , y = r sin (theta) , tan (theta) = y/x


The Attempt at a Solution


Here is my work so far: y=x^(2) so r sin (theta) = (r cos (theta))^2 and r sin (theta) = r^(2) cos^(2) theta. I'm not sure how to move the r's to one side of the equation though. Can I apply tan (theta) = y/x or ? Thanks in advance!
You can divide both sides of your equation by r to get sin(theta) = rcos^2(theta). It's not always legitimate to do this, as you might be losing solutions for r = 0. In this case, r = 0 is still a solution.
 

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