How Do I Correctly Solve This Algebraic Equation Involving e and K?

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Homework Help Overview

The discussion revolves around solving an algebraic equation involving the variable y, a constant K, and an exponential term. Participants are examining the transformation of the equation and its implications for the solution.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to manipulate the equation to isolate y but encounters discrepancies with the expected solution. Another participant provides an alternative approach, leading to a different expression for y. There is a question regarding the accuracy of the original problem statement.

Discussion Status

The conversation has progressed with one participant confirming the alternative method as simpler and potentially more accurate. There is acknowledgment of the original poster's oversight in the equation setup, but no consensus on the final solution has been reached.

Contextual Notes

Participants are working under the assumption that the original equation may have been misstated, which could affect the validity of the solutions being discussed.

franky2727
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ive got (y-1/y+2)=Ke3/4x4where K=+ or- e3c

and I am trying to get to y=(2Ke3/4x4)/(1-Ke3/4x4)

but i keep getting y= (-3+Ke3/4x4)/(Ke3/4x4) can someone please have a go at this to see if its me that's wrong or the answer sheet and if its me which it usualy is can you please write your working step by step? thanks
 
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We have:

[tex] \frac{y-1}{y+2}=KL[/tex]

In which [tex]K=\pm e^{3c}[/tex] and [tex]L=e^{\frac{3}{4}x^4}[/tex]

We now work this out:

[tex] y-1=yKL+2KL[/tex]

[tex] y=yKL+2KL+1[/tex]

[tex] y-yKL=2KL+1[/tex]

[tex] y(1-KL)=2KL+1[/tex]

[tex] y=\frac{2KL+1}{1-KL}[/tex]

This does not correspond to the solution you want to get, but in my opinion this is the correct one, maybe you have not given the correct question?
 
ye that's right sorry i forgot to put the +1 on the end and that way is about 50^2 times simpler than the way i was trying to do it thanks!
 
no problem :smile: sometimes the math becomes easier if you just replace some nasty crap by a single parameter :smile:
 

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