How do I derive an expression for the velocity vector for any α ?

griffith
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Homework Statement
This question is part of a homework set. I have shown my attempt and would like help understanding the concepts involved.
Relevant Equations
md2/dt2(s) = Fcos(as)
A bar of mass m resting on a smooth horizontal plane starts
moving due to the force F of constant magnitude. In the
process of its rectilinear motion the angle α between the direction of
this force and the horizontal varies as α = as, where a is a constant,
and s is the distance traversed by the bar from its initial position.
Find the velocity vector of the bar as a function of the angle α. I have tried solving it for all α in the interval [0, inf] but I was only able to find the velocity vector for the angle α in the interval [0,pi/2].
 

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griffith said:
Find the velocity vector of the bar as a function of the angle α. I have tried solving it for all α in the interval [0, inf] but I was only able to find the velocity vector for the angle α in the interval [0,pi/2].
I assume you're troubled by the fact that when ##\alpha > \pi##, the expression you derived gives you ##v^2<0##.

When ##\alpha = \pi##, what's the velocity of the bar and which way does the force point?
 
vela said:
I assume you're troubled by the fact that when ##\alpha > \pi##, the expression you derived gives you ##v^2<0##.

When ##\alpha = \pi##, what's the velocity of the bar and which way does the force point?
velocity equals 0 and the force vector would point to the left(wrt the pic i drew)
 

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