How do I determine the age of a sample using radiocarbon dating?

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Homework Help Overview

The discussion revolves around determining the age of a carbon sample using radiocarbon dating, specifically focusing on a sample with a given mass and activity. Participants are exploring the implications of the unknown isotope and the necessary equations for calculating age.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to identify the specific isotope of carbon, with suggestions that carbon-14 is likely being referenced. There are attempts to apply the decay equations, but questions arise regarding the unknowns in the equations, particularly the initial quantity of carbon and the half-life.

Discussion Status

Some guidance has been provided regarding the identification of carbon-14 and the application of decay constants. However, participants express uncertainty about how to proceed with the calculations due to unresolved variables.

Contextual Notes

The original poster notes that the problem does not specify the isotope of carbon, which complicates the calculations. There is also mention of needing to consider the activity in relation to the sample's mass.

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Homework Statement


9.2g of carbon got an activity of 1.6Bq, how old is it?

Homework Equations


A = -(lambda)*N
N=No * e ^ -(lambda)*t
(lambda) = ln2/t1/2

The Attempt at a Solution


The question doesn't specify which isotope of carbon it is so halflife remains unknown.
I can't see how to solve this by only knowing the mass and activity.
Could anyone give me pointers?

R
 
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They are most likely referring to carbon-14 dating.
 
Alright in that case we know the half life and can find the decay constant.
Using A = -(lambda)*N we can find N as well (not sure If I need to divide the activity on 9.2g to get it per grams?)
However It still leaves No and t unsolved.

An alternative method is to; N=No * e ^ -(lambda)*t |*(lambda) => A=Ao * e ^ -(lambda)*t
But it seems to get me to the same "deadend" where Ao and t is unsolved.
I thought I might be able to set t=0 to get Ao but that only makes the expression " e ^ -(lambda)*t" equal 1.
Any tips?

R

PS: thanks for fast reply
 
Atoms per mole.
The sample starts out with a certain fraction of it being carbon-14.
Over time the amount of carbon-14 decays.
 

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