MHB How do I find the Euclidean Coordinate Functions of a parametrized curve?

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To find the Euclidean coordinate functions of the parametrized curve α(t) = (cos(t), t^2, 0), the coordinates can be expressed as x = cos(t), y = t^2, and z = 0. The relationship between t and y allows for the substitution t = ±√y, leading to x = cos(√y) for both cases. Since cosine is an even function, the negative root does not change the output, confirming that x = cos(√y) is valid. This approach clarifies the connection between the parameterization and Cartesian coordinates.
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I've been given a curve α parametrized by t :

α (t) = (cos(t), t^2, 0)

How would I go about finding the euclidean coordinate functions for this curve? I know how to find euclidean coord. fns. for a vector field, but I am a bit confused here.

(Sorry about the formatting)
 
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I'm not certain what you mean by "Euclidean Coordinates". Perhaps you mean what I would call "Cartesian Coordinates"- a direct relation of x and y. The equations you have are x= cos(t), y= t^2, z= 0. The second equation can be written $t= \pm\sqrt{y}$ so we get two equations, $t= \sqrt{y}$ and $t= -\sqrt{y}$ and then $x= cos(\sqrt{y})$ and $x= cos(-\sqrt{y})$.

But since cosine is an "even function", $cos(-\theta)= cos(\theta)$, those both give $x= cos(\sqrt{y})$.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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