- #1

devanlevin

[(n+5)/(n-1)]^n

i get [infinity/nifinity]^infinity and i dont see anything to change

i get [infinity/nifinity]^infinity and i dont see anything to change

- Thread starter devanlevin
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- #1

devanlevin

[(n+5)/(n-1)]^n

i get [infinity/nifinity]^infinity and i dont see anything to change

i get [infinity/nifinity]^infinity and i dont see anything to change

- #2

HallsofIvy

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If this weren't in the "precalculus" section, I would recommend using L'Hopital's rule!

- #3

Mark44

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True enough that it's of the indeterminate form [tex]1^\infty[/tex], but it's not necessarily equal to 1. Another limit with this form is lim (1 + 1/n)^n, for n approaching [tex]\infty[/tex]. The limit here is the natural number, e.

If this weren't in the "precalculus" section, I would recommend using L'Hopital's rule!

- #4

devanlevin

all true, but the limits anwer is e^6

- #5

HallsofIvy

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True enough that it's of the indeterminate form [tex]1^\infty[/tex], but it's not necessarily equal to 1. Another limit with this form is lim (1 + 1/n)^n, for n approaching [tex]\infty[/tex]. The limit here is the natural number, e.

Yes! Mark44 essentially gives that! Dividing, (n+5)/(n-1)= 1+ 6/(n-1) so ((n+5)/(n-1))all true, but the limits anwer is e^6

His response was far more helpful than mine was!

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