How Do I Find the Peak Magnitude of H(jω) in a Circuit?

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SUMMARY

The peak magnitude of the transfer function H(jω) occurs at ω=0, as determined by analyzing the expression (R/L)/[sqrt((R+RI)/L)² + ω²]. The minimum value of the denominator leads to the maximum magnitude, confirming that any other value of ω results in a lower magnitude. This conclusion is essential for understanding circuit behavior in response to varying frequencies.

PREREQUISITES
  • Understanding of transfer functions in circuit analysis
  • Familiarity with complex frequency variables (jω)
  • Knowledge of circuit components, specifically resistors (R) and inductors (L)
  • Basic calculus for optimization techniques
NEXT STEPS
  • Study the concept of transfer functions in more detail
  • Learn about the impact of frequency on circuit behavior
  • Explore optimization techniques for finding maxima and minima in functions
  • Investigate the role of impedance in AC circuit analysis
USEFUL FOR

Students in electrical engineering, circuit designers, and anyone studying the frequency response of circuits will benefit from this discussion.

jean28
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Hey guys. I'm doing some homework for my circuits class and was wondering if anyone could help me with this question.

How do I determine the value of ω will the magnitude of H(jω) be maximum??

In my case, the magnitude of the transfer function is (R/L)/ [sqrt((R+RI)/L)2 + ω2)]
 
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jean28,

Hey guys. I'm doing some homework for my circuits class and was wondering if anyone could help me with this question.

How do I determine the value of ω will the magnitude of H(jω) be maximum??

In my case, the magnitude of the transfer function is (R/L)/ [sqrt((R+RI)/L)2 + ω2)]

You do it by inspection. You can easily see that the maximum will occur when the denominator is at its smallest value. That happens when ω=0. Any other value lowers the magnititude of H(jω).

Ratch
 

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