How do I find the phase difference between two oscillators

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SUMMARY

The discussion focuses on calculating the phase difference between two harmonic oscillators represented by the equations x(t) = 0.4 cos(2.1t) and x(t) = 0.4 cos((π/2)t + π). The key to finding the phase difference is substituting t = 1 into both equations and then subtracting the resulting angles. This method effectively determines the phase difference at the specified time.

PREREQUISITES
  • Understanding of simple harmonic motion
  • Familiarity with trigonometric functions
  • Knowledge of phase angle concepts
  • Ability to perform basic arithmetic operations with angles
NEXT STEPS
  • Study the definition and properties of phase in harmonic motion
  • Learn how to manipulate trigonometric equations for phase calculations
  • Explore the concept of angular frequency in oscillatory systems
  • Investigate the effects of phase difference on interference patterns
USEFUL FOR

Students studying physics, particularly those focusing on oscillatory motion, as well as educators looking for examples of phase difference calculations in harmonic oscillators.

Fysicsfailure
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Homework Statement



Find the phase difference between two harmonic oscillators at time t=1

Homework Equations


I've already found x(t)= .4 cos(2.1t) and x(t)= .4cos((pi/2)t + pi)


The Attempt at a Solution


I don't really know where to begin
 
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Hello, and welcome to PF!

Start with recalling (or finding) the definition of the word "phase" for simple harmonic motion.
 
Hey thanks! :)

Oh wow...Okay now I got it. Just plug in 1 for t and subtract the two terms in the parentheses. Thanks for the lead!
 

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