How do I find two vectors that are orthogonal to each other?

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Homework Help Overview

The discussion revolves around finding a nonzero vector that is orthogonal to a given vector within a specific span. The context involves linear combinations and the properties of vector projections.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the requirement for the dot product to equal zero for orthogonality and explore the concept of vector projections. There is questioning of the relevance of certain vectors to the problem and attempts to clarify the method for finding orthogonal vectors.

Discussion Status

The discussion includes attempts to clarify the relationship between the vectors and the methods for finding the orthogonal vector. Some participants suggest using vector projections, and there is acknowledgment of successful application of these ideas by one participant.

Contextual Notes

There is mention of constraints regarding the components of the vector being sought, as well as confusion about the relevance of certain vectors in the problem setup.

nickerst
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1. Find a nonzero vector v in span {v2,v3} such that v is orthogonal to v3. Express v as a linear combination of v2 and v3


2. v1= [3 5 11] v2= [5 9 20] v3= [11 20 49]


3. I know that the dot product of v and v3 must equal zero. And that v must have components between 5 and 11, 9 and 20, and 20 and 49. But I can't find the solution. I tried using pythagoras' theorem for vectors, as well as orthogonal projections but both don't work.
 
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What does v1 have to do with the question? Do you know how to find the vector projection of v2 on v3? If so, you can just subtract it from v2 to get the orthogonal projection vector.
 
LCKurtz What does v1 have to do with the question? Do you know how to find the vector projection of v2 on v3? If so, you can just subtract it from v2 to get the orthogonal projection vector.

I suppose v1 doesn't have anything to do with the question.

Is the vector projection of v2 onto v3 = [(v2 dot v3) / Length(v3) squared] times v3? If so I then just subtract it from v2 and that's my answer?
 
Thank you very much LCKurtz! It worked!
 

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