How Do I Find Vector Components Using Trigonometric Formulas?

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Homework Help Overview

The discussion revolves around finding vector components using trigonometric formulas, specifically in the context of physics problems involving initial velocity and angles. Participants are exploring how to determine these components when certain information, like the angle, is not directly provided.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need for angles to find vector components and question how to proceed without knowing the angle. Suggestions include assigning a variable to the angle and using equations of motion to solve for it. There is also a discussion about the mathematical implications of having multiple angles for a given range.

Discussion Status

The discussion is active, with participants expressing confusion and seeking clarification on the relationship between angles and vector components. Some guidance has been offered regarding the assignment of an angle variable and the reasoning behind multiple solutions, but no consensus has been reached.

Contextual Notes

Participants are operating under the assumption that angles must be between 0 and 90 degrees, and there is a noted confusion regarding the physical interpretation of mathematical results, particularly concerning the sine function and its values.

meganw
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Vector Angle Problem - Answered, thanks! =)

1. The problem statement

Find Vector Components

Homework Equations



trig formulas are important here: sin =o/h, cos=a/h, tan=o/a

The Attempt at a Solution



Thanks for the help! =)
 
Last edited:
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meganw said:
Is 7.6 the initial vertical velocity? Or horizontal? Sorry I'm just confused.

It's just initial velocity, which has both vertical and horizontal components.
 
But how do I find those components if I don't know the angle?
 
Just assign the angle some name, like [itex]\theta_0[/itex]. Then with the given info and the equations of motion, solve for [itex]\theta_0[/itex].
 
Thank you so much!
 
Last edited:
meganw said:
Thank you so much! I didn't realize I could do that sort of thing...thanks again! =)

Is there any "physics" reason why there are 2 angles...mathematically sin x = 1.5 at various values of x...

sin x must be between 0 and 1...

Actually there's one way to think about why there are two angles... Think about the range when the angle is 0 and the angle is 90... in both cases the range is 0. so the range gets larger as you go up from 0... and as you go down from 90... so that gives an intuitive reason why there are two angles for each range... for a particular range... if you have an angle close to 0... then there's another angle close to 90...

When you solve for [tex]\theta_0[/tex] two solutions will appear... note: you're restricted to angles between 0 and 90.
 
meganw said:
Is there any "physics" reason why there are 2 angles...mathematically sin x = 1.5 at various values of x...

I do not know the "physical reason" behind it. But since we are talking about angles and distances, I guess I will resort to saying "the math works that way." :)
 
Wow, thanks both of you! I really appreciate it, you have no idea! =)
 

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