How do I find velocity when force is not a constant?

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Homework Help Overview

The discussion revolves around finding velocity when the force acting on an object is not constant but varies as a function of distance. The specific force function given is F(x) = 2.5 - x^2, leading to the expression for acceleration as a = (2.5 - x^2)/m, where m represents mass.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the integration of the force function to derive velocity, questioning how mass factors into their calculations. There is also a discussion about the validity of integrating acceleration with respect to position versus time.

Discussion Status

Some participants have provided guidance on the integration process and the assumption of constant mass. However, there is recognition of a misunderstanding regarding the relationship between acceleration and velocity, indicating that further exploration is needed to clarify the correct approach.

Contextual Notes

Participants are grappling with the implications of integrating acceleration with respect to the wrong variable and are considering the use of the chain rule to address this issue. The discussion reflects a mix of assumptions and interpretations regarding the problem setup.

DBaima22
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how can i find velocity if force is not constant, but a function of distance. I tried integrating the equation for the force, but that doesn't account for the mass of the object.

the given equation for the force is F(x)=2.5-x^2, where x is distance and since F=ma I have
a=(2.5-x^2)/m.

When I tried integrating it I got velocity= -1/3x^3+2.5x which does not account for mass

Is there a quotient rule for integration?
 
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Welcome to PF, DBaima22 :smile:
DBaima22 said:
how can i find velocity if force is not constant, but a function of distance. I tried integrating the equation for the force, but that doesn't account for the mass of the object.

the given equation for the force is F(x)=2.5-x^2, where x is distance and since F=ma I have
a=(2.5-x^2)/m.

When I tried integrating it I got velocity= -1/3x^3+2.5x which does not account for mass

Is there a quotient rule for integration?

It's completely reasonable to assume that the mass of the object is constant. Therefore, this becomes trivial. You can use the relevant integration property, namely that if g(x) = f(x)/a where a = const. then:

\int g(x)\,dx = \int \frac{f(x)}{a}\,dx = \frac{1}{a}\int f(x)\,dx

If something is constant (i.e. it has no dependence on the integration variable), then it can be brought outside the integral.
 
So, just to be clear, if acceleration is (2.5-x^2)/m. I can write velocity as
v= -1/3x^3+2.5x/mass?
 
DBaima22 said:
So, just to be clear, if acceleration is (2.5-x^2)/m. I can write velocity as
v= -1/3x^3+2.5x/mass?

Yes. BUT there is another problem with your solution that I only just realized (because I wasn't paying close enough attention before). You CAN'T get velocity by integrating acceleration with respect to position. Velocity is the integral of acceleration with respect to TIME. So you'll have to work a little bit harder to figure out how to get velocity. :wink: Hint: the chain rule may be of use here.
 

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