How do I interpret multiple principal stresses for 3D loading with shear?

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Discussion Overview

The discussion centers on the interpretation of multiple principal stresses in the context of three-dimensional loading with shear. Participants explore the application of principal stress formulas and the implications for using the von Mises criterion to determine yielding limits.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants note that applying the principal stress formula in a 3D context leads to obtaining six principal values, which complicates the use of the von Mises criterion for finding the yielding limit.
  • Others argue that the 2D equations cannot be used for 3D situations and suggest solving the eigenvalue problem to determine principal directions and stresses.
  • A participant questions whether the eigenvectors correspond to their respective directions and raises the issue of multiple vectors for a single eigenvalue.
  • Another participant asserts that there is only one 3D vector for each eigenvalue, suggesting a clarification on the relationship between eigenvalues and eigenvectors.

Areas of Agreement / Disagreement

Participants express differing views on the interpretation of principal stresses and the relationship between eigenvalues and eigenvectors. The discussion remains unresolved regarding the implications of having multiple vectors for a single eigenvalue.

Contextual Notes

The discussion highlights limitations in applying 2D stress analysis methods to 3D scenarios and the need for clarity on the mathematical relationships involved in eigenvalue problems.

vin300
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For 3 D loading with shear, if I use the principal stress formula, say for x-y direction, two principal stresses are obtained. If the same is applied to y-z, two more principal are obtained, with one supposed to be common, but not. Thus I obtain six principal values, which cannot be used with the von mises criterion to find yielding limit.
 
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vin300 said:
For 3 D loading with shear, if I use the principal stress formula, say for x-y direction, two principal stresses are obtained. If the same is applied to y-z, two more principal are obtained, with one supposed to be common, but not. Thus I obtain six principal values, which cannot be used with the von mises criterion to find yielding limit.
You can't use the 2D equations for a 3D situation. To determine the principal directions and stresses in 3D, you need to solve the following eigenvalue problem: ##\vec{\sigma} \centerdot \vec{n}=\lambda \vec{n}##, where sigma is the stress tensor, n is a unit vector in one of the three principal directions, and lambda is the corresponding principal stress. This equation leads to 3 homogeneous linear algebraic equations in the components of n.
 
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After finding the eigen values, do the eigen vectors represent their direction? If they do, what do I make of more than one vector for one lambda?
 
vin300 said:
After finding the eigen values, do the eigen vectors represent their direction? If they do, what do I make of more than one vector for one lambda?
The is only one 3D vector for each lambda.
 

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