How do I manipulate this to the form desired?

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Homework Help Overview

The discussion revolves around manipulating an equation involving a logarithmic expression to achieve a desired form. The original equation includes a natural logarithm and is related to a physical context, likely involving fluid dynamics or thermodynamics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants express uncertainty about how to eliminate the natural logarithm from the equation. Some suggest using approximations, specifically the approximation of the logarithm for small values. Others mention properties of logarithms and inquire about resources for further understanding.

Discussion Status

Participants are exploring different mathematical approaches to manipulate the equation. Some guidance has been offered regarding the use of approximations and properties of logarithms, but there is no explicit consensus on the method to be used.

Contextual Notes

There is a mention of the approximation ##\ln(1+a) \approx a## being valid for small values of ##a##, which is a key point under discussion. The conversation also touches on the Taylor series expansion of the logarithm, indicating a focus on mathematical foundations.

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Homework Statement


I want to manipulate an equation to suit a desired form.

Homework Equations


##(-h^2/2uc)*(dp/dx)*ln((1+c*(x/h)^2)/(1+c))##

becomes

##-(h^2/2u)*(dp/dx)*(1-(x/h)^2)##

The Attempt at a Solution



I have no idea, I'm not even sure how the natural log disappears. [/B]
 
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shreddinglicks said:

Homework Statement


I want to manipulate an equation to suit a desired form.

Homework Equations


##(-h^2/2uc)*(dp/dx)*ln((1+c*(x/h)^2)/(1+c))##

becomes

##-(h^2/2u)*(dp/dx)*(1-(x/h)^2)##

The Attempt at a Solution



I have no idea, I'm not even sure how the natural log disappears. [/B]

They are using the approximation ##\ln(1+a) \approx a## valid when ##a## is small. Try that along with other rules about logs.
 
Dick said:
They are using the approximation ##\ln(1+a) \approx a## valid when ##a## is small. Try that along with other rules about logs.

I see:

Use ##ln(x/y) = ln(x) - ln(y)##

The rest is simple.

Is there a link to somewhere online showing that approximation you gave? Just curious.
 
shreddinglicks said:
Is there a link to somewhere online showing that approximation you gave? Just curious.

I don't know any good links. But approximations like this generally come from taking the first terms of the Taylor series. ##\ln(1+x)=x-
\frac{x^2}{2}+\frac{x^3}{3}-\frac{x^4}{4}+\ldots## Keeping just the first term gives the approximation. Similarly, ##\sin(x) \approx x## etc.
 
Dick said:
I don't know any good links. But approximations like this generally come from taking the first terms of the Taylor series. ##\ln(1+x)=x-
\frac{x^2}{2}+\frac{x^3}{3}-\frac{x^4}{4}+\ldots## Keeping just the first term gives the approximation. Similarly, ##\sin(x) \approx x## etc.

Thanks.
 

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