How do I prove |xy| = |x| * |y|?

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The discussion focuses on proving the mathematical statement |xy| = |x| * |y|, utilizing the definition of absolute value. Participants emphasize the importance of breaking the proof into cases: when either x or y is zero, when both are positive, and when one is positive and the other is negative. A valid proof must start from the definition of absolute value, which states |x| = x if x ≥ 0, |x| = -x if x < 0, and |x| = 0 if x = 0. The proof should logically demonstrate that |xy| equals |x| * |y| through these cases.

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  • #31
This massive off-topic misunderstanding over the meaning of √x was a bit unwarranted.

As an aside, proving the conjecture with |x| defined as √(x2) is rather trivial.
 
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  • #32
epenguin said:
Surely not true. √9 = ± 3. √-9 = ± 3 i
D H already dealt with this, but I'll say a bit more. It's true that 9 has two square roots, but the symbol √9 is generally recognized to mean the positive square root, or 3.
epenguin said:
It would be just like the one already given for |x|. Instead of we'd have something like |x|= √(x²) if √(x²)> 0, |x|= -√(x²) if √(x²)<0, and |x|=0 if x=0, introducing and then inverting an operation to no purpose.
For any real number x, √(x2) is always nonnegative.
 
  • #33
D H said:
1MileCrash is correct. This is not. √9 is 3, never -3. √x is the function that uniquely maps the non-negative reals to the non-negative reals such that (√x)2=x. This function can be extended to the negative reals and to all of the complex numbers by defining a a branch cut. There are some problems with this extension (e.g., (ab)c = abc is no longer universally true), but √z still a function, not a multifunction.

OK I guess you're right, now I think of it otherwise we wouldn't write ± in the quadratic solution formula.

However I maintain the appearance of greater simplicity is merely verbal or notational and apparent - you happen to have a convention for something a bit elaborate, you have this convention because you do these operations often. But it is not simpler than Avodyne's definition. It represents an operation on x which is then inverted with a condition. Two unnecessary operations which no one in their senses would ever do. Of course anyone presented with calculating √(x2), say √(-237124.6292) can do it in their heads, write the answer immediately and what do they actually do? They write |x| as calculated according to the Avodyne's definition! :-p
 
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  • #34
epenguin said:
OK I guess you're right, now I think of it otherwise we wouldn't write ± in the quadratic solution formula.

However I maintain the appearance of greater simplicity is merely verbal or notational and apparent - you happen to have a convention for something a bit elaborate, you have this convention because you do these operations often. But it is not simpler than Avodyne's definition. It represents an operation on x which is then inverted with a condition. Two unnecessary operations which no one in their senses would ever do. Of course anyone presented with calculating √(x2), say √(-237124.6292) can do it in their heads, write the answer immediately and what do they actually do? They write |x| as calculated according to the Avodyne's definition! :-p

It's not just an appearance of greater simplicity. It is simpler in practice. This proof is one example, just as any proof involving the absolute value of a real number. Other examples aren't hard to find. What is the derivative of |x|? That any person would use Avodyne's definition for a quick computation means it is a useful way to quickly compute something, not that it is a better working definition in proofs or studying qualities of the function.

And another thing I want to mention is that √(x2) isn't just chosen because it's a "function and inverse" that works out like we want it to. Consider that the absolute value for a complex number (the set of which is a superset of the reals, so this MUST hold in the reals too) is |a + bi| = √(a2 + b2). That's what it is, there is no way to define it with another function and its inverse. |x| = √(x2) is the exact same thing, the imaginary component is 0. That's why we say that |x| = √(x2) and not some other "function and inverse." It does not require any conditional at all (I still don't see what you mean by "inverted with a condition"), and is guaranteed to work every time.
 
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