Calculate Free Fall Time for 10.0m w/ g=1/6 Earth's g

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Homework Help Overview

The discussion revolves around calculating the time it takes for an object to fall 10.0 meters under a gravitational acceleration of one sixth that of Earth's gravity. Participants explore the implications of using a modified gravitational constant and the conditions of free fall.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the lack of initial velocity information and its impact on applying kinematic equations. Questions arise regarding the relationship between acceleration, time, and displacement in the context of free fall. There is also exploration of the definitions of initial and final velocity in different scenarios.

Discussion Status

The conversation is ongoing, with participants providing guidance on identifying relevant kinematic equations and clarifying concepts related to initial and final velocities. Multiple interpretations of the problem setup are being examined, particularly regarding the conditions under which the object is released.

Contextual Notes

Participants note the absence of specific velocity values and question assumptions about the initial state of the object being dropped. There is a focus on understanding the definitions of terms used in the problem and how they apply to the scenario presented.

Balsam
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Homework Statement


Calculate the length of time it would take for an object to fall 10.0m if g were one sixth the value of Earth's g.

g=1/6(-9.8)= -1.633333333 m/s^2

a=-1.633333333m/s^2
displacement=10.0m[down]

Homework Equations


Maybe one of the big 5 kinematics equations? Or maybe a=change in velocity/time.

The Attempt at a Solution


I didn't have enough variables to use any of the listed equations. This is because the question does not give any velocity values and I don't know how to solve for them. How would you do this problem. Note: According to my book, the correct answer is 3.5s.
 
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Balsam said:

Homework Statement


Calculate the length of time it would take for an object to fall 10.0m if g were one sixth the value of Earth's g.

g=1/6(-9.8)= -1.633333333 m/s^2

a=-1.633333333m/s^2
displacement=10.0m[down]

Homework Equations


Maybe one of the big 5 kinematics equations? Or maybe a=change in velocity/time.

The Attempt at a Solution


I didn't have enough variables to use any of the listed equations. This is because the question does not give any velocity values and I don't know how to solve for them. How would you do this problem. Note: According to my book, the correct answer is 3.5s.

The object falls - it means its initial velocity is zero. What relation exist between constant acceleration, time, and displacement?
 
ehild said:
The object falls - it means its initial velocity is zero. What relation exist between constant acceleration, time, and displacement?
I'm not sure. what do you mean?
 
Balsam said:
I'm not sure. what do you mean?
Knowing that the initial velocity is zero, which one of the five SUVAT equations relates constant acceleration, time, distance, and initial velocity?

Scan the list of these equations and use a process of elimination to narrow your choices to the correct equation.
 
SteamKing said:
Knowing that the initial velocity is zero, which one of the five SUVAT equations relates constant acceleration, time, distance, and initial velocity?

Scan the list of these equations and use a process of elimination to narrow your choices to the correct equation.
Don't objects have a non-zero initial velocity when dropped?
 
Balsam said:
Don't objects have a non-zero initial velocity when dropped?
The problem meant that the object was hold and then released and let to fall. What is the initial velocity?
 
Last edited:
ehild said:
The problem meant that the object was hold and then released and let to fall. What is the initial velocity?

I thought that the initial velocity meant the velocity right after the motion began, just like final velocity is the velocity right before motion ends, not the velocity when the motion is over and the object is at rest.
 
The "final Velocity" isn't always the Velocity just before the object stops moving. It depends on the problem. For example there is a common problem that involves an object falling past a window - after passing the window it keeps falling. When ,you break the problem down the final Velocity you plug into one of the suvat equations is typically the Velocity as it passes the bottom of the window.

The initial velocity when an object is dropped is usually zero but there are situations where it isn't. For example when it's dropped from a helicopter that is ascending or descending.
 
CWatters said:
The "final Velocity" isn't always the Velocity just before the object stops moving. It depends on the problem. For example there is a common problem that involves an object falling past a window - after passing the window it keeps falling. When ,you break the problem down the final Velocity you plug into one of the suvat equations is typically the Velocity as it passes the bottom of the window.

The initial velocity when an object is dropped is usually zero but there are situations where it isn't. For example when it's dropped from a helicopter that is ascending or descending.

Why is the final velocity in the window problem the velocity as it passes the bottom of the window?
 
  • #10
Balsam said:
I thought that the initial velocity meant the velocity right after the motion began,
What is the velocity of the object right after the accelerating motion began if it was in rest before? You keep a pebble in your hand. What is the velocity of the pebble? Then you open your hand and let the pebble fall out. What is the velocity of the pebble at the instant when you release it?
"Initial" and "final" are defined by the problem. If you observe a pot falling in front of a window, you observe it from the room during the time it moves from the top of the window down the bottom.
 
  • #11
Balsam said:
Why is the final velocity in the window problem the velocity as it passes the bottom of the window?

Why not? It depends on the actual version of the question but the most common version of the problem requires you to solve it in two phases, in the first phase the final velocity is the top of the window. That value is then used as the initial velocity for the second phase of the solution. In the second phase it seems reasonable to label the velocity at the bottom of the window the final velocity although you can solve the problem without calculating it.
 

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