How do I simplify this equation further?

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Discussion Overview

The discussion revolves around simplifying an equation that relates variables i and r, with constants D and T involved. Participants are exploring algebraic manipulation techniques to achieve this simplification.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents the equation (3+3r+r^2)/(3+3i+i^2)=d and seeks further simplification.
  • Another participant suggests multiplying both sides by (1+r)^3 to eliminate denominators and then moving all terms to one side.
  • There is a clarification regarding the notation i!=0, where one participant explains that it means i is not equal to zero, not factorial.
  • A different approach is proposed, suggesting to replace (1+r) with x, establishing a common denominator, and then simplifying the equation further.
  • Participants discuss the importance of avoiding division by zero in their manipulations.

Areas of Agreement / Disagreement

Participants generally agree on the methods of algebraic manipulation but do not reach a consensus on the specific steps or the effectiveness of different approaches.

Contextual Notes

Some assumptions regarding the values of i and r are implied, particularly concerning their non-zero status, which is crucial for the proposed manipulations. The discussion does not resolve the overall simplification process or the correctness of each method suggested.

musicgold
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Hi,

Please see the attached document. I don’t know how simplify the equation further. I am trying to find the relationship between i and r. D and T are constants.

Thanks.
 

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(3+3r+r^2)/(3+3i+i^2)=d

if I haven't made any mistakes, if i!=0, if 1+r!=0
 
Thanks Bill.
Your reply is not clear to me. Would you be able to show your steps?

Also, is that factorial in i!=0, if 1+r!=0 ?
 
musicgold said:
Thanks Bill.
Your reply is not clear to me. Would you be able to show your steps?

Also, is that factorial in i!=0, if 1+r!=0 ?
No, it's not factorial. The C language notation != is sometimes used for ≠, and I believe that's what Bill meant.
 
Multiply both sides by (1+r)^3 to get rid of the denominators. Move everything to one side of the =. Expand all the resulting powers. Discard all the v-v terms for every expression v. Your t disappears in the process. Push d to the other side of the =. Do a divide to isolate d. Divide numerator and denominator by the common terms.

And yes != was "not equal", all the divisions and multiplications in this process depend on your not multiplying or dividing by zero or the result will be meaningless.

All this is just basic algebraic manipulation and I don't even see any tricky bits.
 
Thanks Bill. That is helpful.
 
Make your life easier by replacing (1+r) with x. Have a common denominator of x^3 and cancel it out by cross multiplying or just multiplying both sides by x^3. Remove all like terms from both sides. Then replace x with 1+r. Expand the terms and remove all like terms on both sides. At this point you should see that T cancels out completely or I made a mistake. Good Luck.
 

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