How do I simplify this resistor circuit for my homework?

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SUMMARY

The discussion focuses on simplifying a resistor circuit for homework, specifically addressing the combination of resistors in series and parallel. The user successfully combines the bottom branch of the circuit to achieve an equivalent resistance (Req) of 60 Ohms. They identify that the top right resistor is shorted and thus irrelevant to the calculation. The final equivalent resistance is calculated as 12 Ohms using the formula for parallel resistors.

PREREQUISITES
  • Understanding of Ohm's Law
  • Familiarity with series and parallel resistor combinations
  • Basic algebra for manipulating equations
  • Knowledge of circuit diagrams and notation
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  • Study the principles of series and parallel circuits in detail
  • Learn how to analyze complex resistor networks using Thevenin's and Norton's theorems
  • Practice problems involving equivalent resistance calculations
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This discussion is beneficial for students studying electrical engineering, particularly those preparing for exams involving circuit analysis and resistor networks.

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Homework Statement



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Homework Equations



Resistors in Series = R1 + R2 + R3... = Req
Resistors in Parallel = 1/R1 + 1/R2 + 1/R3 ... = 1/Req

The Attempt at a Solution



Studying for a test. This sample exam went pretty well. I am having trouble with 3 out of the 20. I can't figure this one out.

The bottom branch can be combined to be Req = 30 + 30 = 60 Ohms

From there, I can't seem to find a way to combine the rest. I have the answer (B) but I can't collapse the circuit.
 
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The top right resistor is shorted out, so it has no effect. Imagine that it's erased from the diagram.
The center point and point b are the same point.
You have 30 in parallel with 30 in parallel with (30+30).
1/[(1/30) + (1/30) + (1/{30+30})] = 12 ohms.
 
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