How do I solve exponentials with base e?

  • Thread starter Thread starter LinkMage
  • Start date Start date
  • Tags Tags
    Base
Click For Summary
SUMMARY

The discussion centers on solving equations involving the exponential function with base e, specifically addressing the equation x^3 + e^(2x) + 8 = 0. Participants emphasize that exact solutions are not feasible, advocating for graphical or iterative methods instead. Key techniques include taking the natural logarithm of both sides of equations, such as ln(e^x) = ln(20), to simplify and isolate variables. The conversation highlights the importance of understanding logarithmic properties, particularly ln(a^b) = b*ln(a), for solving exponential equations.

PREREQUISITES
  • Understanding of exponential functions and their properties
  • Knowledge of natural logarithms and their applications
  • Familiarity with graphical methods for solving equations
  • Basic algebraic manipulation skills
NEXT STEPS
  • Learn how to apply the natural logarithm to solve exponential equations
  • Study graphical methods for finding roots of polynomial and exponential equations
  • Explore iterative methods such as the Newton-Raphson method for root finding
  • Review logarithmic identities and their applications in solving equations
USEFUL FOR

Students, educators, and professionals in mathematics or engineering fields who are dealing with exponential equations and require a deeper understanding of logarithmic functions and their applications.

LinkMage
Messages
18
Reaction score
0
I don't know how to solve x for things like e^x=20.
The problem I have to solve is x^3+e^(2x)+8=0
Can anyone help, please?
 
Physics news on Phys.org
have you learned logarithms?

what is the natural log of e^x?
 
LinkMage said:
I don't know how to solve x for things like e^x=20.
The problem I have to solve is x^3+e^(2x)+8=0
Can anyone help, please?

You won't be able to find an exact solution to your problem so you will have to resort to solving it graphically or by iteration.
 
The exponential function is the inverse function of the natural logarithm.
therefore ln(e^{f(x)}) = f(x). In your example, like any equation, what you do on one side of the equation must be done on the other side. You can take the natural log of both sides ln(e^{x})=ln(20)
Then using the property I gave above you should be able to solve for x

Once you have practised using the idea given above, you can then tackle your second question. You may want to bring your x-terms on one side of equation and any other terms, to the other side of equation. As with the first query, take the natural log of both sides. Though you eliminate your exponential function, you may still have some natural log terms left. That's okay, by substitution of values for x you should arrive at correct value f(x) to your question.

Edit: By plotting the values of x you substitute and resulting values f(x), as Tide suggests; by observing the trend in your graph, you may find (or at least narrow down) your solutions more quickly.
 
Last edited:
You mean I just replace values for x until I get that the equation equals 0. That's what I did first and got aproximately -2.001. I was just wondering if I could solve the equation instead of replacing numbers.
 
Anytime you have a logarithm, there are different rules that you need to know. For the first example you gave the one you need to know is this.

\log_{a}b^c=c\log_{a}b it also follows that

\ln a^b=b\ln a

So when you are given something like e^x=20, how can you apply this rule to solve that?

For your second problem, as others have said, you cannot solve for x explicity so another method must be used.
 
zwtipp05 said:
have you learned logarithms?

what is the natural log of e^x?
it is equal to x,

well, I just wanted to remind theOP
 

Similar threads

Replies
25
Views
1K
  • · Replies 48 ·
2
Replies
48
Views
4K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
4
Views
1K
Replies
2
Views
1K
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
952