How do I solve these physics problems involving variables and equations?

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SUMMARY

This discussion focuses on solving physics problems involving variables and equations, specifically related to electric potential and electric fields. The user identifies multiple-choice questions regarding potential and scalar quantities, concluding that the net potential is zero at specific points along the perpendicular bisector of charges. The user also applies the relationship between electric field (E) and potential (V) using the equations E = - (V/d) and V = - E . d to derive solutions for the problems presented.

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  • Understanding of electric potential and electric fields
  • Familiarity with scalar quantities in physics
  • Knowledge of vector calculus, specifically dot products
  • Ability to solve multiple-choice questions in physics
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  • Study the concept of electric potential and its applications in electrostatics
  • Learn how to calculate electric fields using Gauss's Law
  • Explore the relationship between electric potential and electric field strength
  • Practice solving multiple-choice physics problems to improve problem-solving skills
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Students studying physics, particularly those focusing on electromagnetism, as well as educators looking for effective problem-solving strategies in electric potential and fields.

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The first one on the left is a Multiple Choice question. Just the mention of variables shuts down my brain. I'm still researching for the equation for the pbm.


The pbm in the right upper corner i think it's C and E. (by simply looking at it)

The pbm on the bottom right corner i used -E times delta r... I got -17.59.

Any help in the next 20-30 minutes will be much appreciated... as it'll double my homework score...
 
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Potential is a scalar quantity. The distance of the points in all the 3 cases from the charges is same (they lie on the perpendicular bisector). So the net potential will be zero along these points (all are equal = 0).

For the right upper corner, consider the other point where the potential may be zero. There are three possibilites - right of +Q, between the charges and left of -2Q. One case is already given - right of +Q. Left of -2Q will be ruled out (Why?). So one case is left. Solve. (d/3)

For 3rd one use E = - (V/d)
or V = - E . d (E dot product d).
where d is the radius vector pointing from B to A.
 
For the second question answer is D+(2D/3) = 5D/3
 

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