How do i solve this question? please maths exam tm?

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The discussion focuses on solving a mathematical problem involving the perimeter of a rectangle, specifically with a perimeter of 140 cm and a length-to-width ratio of 4:3. The solution involves using the formula for perimeter, P = 2*(length + width), to express the length in terms of width. By substituting this expression into the perimeter equation, the width can be calculated, followed by determining the length and finally calculating the area as length multiplied by width.

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How do i solve this question?? urgent please maths exam tm?

The question is:
The perimeter of a rectangel is 140cm. The length with width ratio is 4:3. Find the area??

Could someone please help me with this question??
 
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Well, you're given the value of the perimeter, and you should know that the perimeter is just the sum of the sides of the rectangle, which is twice the sum of the length plus width: perimeter = 2*(length + width).

You know that length/width = 4/3, so you can express length in terms of width, plug into your perimeter expression above, and solve for the width. Then you can calculate the length from the width.

Finally, area is just length*width.
 

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