How do I translate periodic motion to translational motion?

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Homework Help Overview

The problem involves translating periodic motion from an engine's operation into translational motion of a race car. It specifically examines the relationship between the frequency of sound emitted by the engine and the car's speed, as well as the engine's revolutions per minute.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the frequency of the engine's sound and the number of revolutions, questioning the use of π in calculations and exploring how to derive the car's speed from the given frequency and revolutions per kilometer.

Discussion Status

Some participants have offered guidance on how to approach the problem, suggesting that the original poster reconsider the relationship between the engine's revolutions and the emitted sound frequency. Multiple interpretations of the engine's operation are being explored, particularly regarding the timing of the sounds produced by the pistons.

Contextual Notes

There is a discussion about the nature of the engine (4-stroke vs. 2-stroke) and the implications of the sharp sounds produced by the pistons, which may affect the calculations. Participants also mention preferences for working in different units (meters and seconds vs. kilometers and hours).

Eclair_de_XII
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Homework Statement


"Each piston of an engine makes a sharp sound every other revolution of the engine. (a) How fast is a race car going if its eight-cylinder engine emits a sound of frequency 750 Hz, given that the engine makes 2000 revolutions per kilometer? (b) At how many revolutions per minute is the engine rotating?"

Homework Equations


##f=750s^{-1}=750Hz=\frac{375}{\pi}\frac{rev}{s}##
##r=\frac{2000rev}{1km}##

The Attempt at a Solution


##v=\frac{f}{r}=\frac{1km}{2000rev}(\frac{375}{\pi}\frac{rev}{s})=\frac{3}{16\pi}\frac{km}{s}=\frac{675}{\pi}\frac{km}{hr}##

The book says that it's ##v=340\frac{km}{hr}##. I don't understand what I am doing wrong.
 
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I'm not sure why you are using π. You just need to consider that one revolution of the engine results in the car moving a distance of 1/2000 km. And from the frequency of 750 Hz, you should be able to calculate how many revolutions the engine makes every second. From that you should be able to calculate the distance the car moves every second.

By the way, I did not get the same answer as the book, but I rushed my calculation.
 
TomHart said:
And from the frequency of 750 Hz, you should be able to calculate how many revolutions the engine makes every second.

So ##750 Hz## is 750 cycles per second, which is, I take it, to be 750 revolutions per second?
 
Eclair_de_XII said:
So 750Hz750Hz750 Hz is 750 cycles per second, which is, I take it, to be 750 revolutions per second?
I believe what they are implying is that it is a 4-stroke engine and that it makes a sharp sound when the spark plug fires causing combustion in a given cylinder. In other words, the combustion (and sharp sound) does not occur every revolution for each piston; it occurs every other revolution for each piston. But you have to remember that there are 8 pistons and that each piston is making a sharp sound every other revolution. And they are basically telling you that there are 750 sharp sounds every second. So based on that you can calculate the number of rotations (Edit: revolutions) the engine makes every second.

Edit 2: I think it would simplify it if you work in meters and seconds and then convert to km/hr at the end. That's just my personal preference though.
 
Last edited:
TomHart said:
In other words, the combustion (and sharp sound) does not occur every revolution for each piston; it occurs every other revolution for each piston. But you have to remember that there are 8 pistons and that each piston is making a sharp sound every other revolution. And they are basically telling you that there are 750 sharp sounds every second.

Okay, so there is one sharp sound every two revolutions, then. There are eight revolutions, so four sharp sounds... I'm guessing: ##v=\frac{750rev}{4s}(\frac{1km}{2000rev})(\frac{3600s}{1hr})=337.5\frac{km}{hr}##.
 
That looks right to me. After looking at your result, I realize that my answer was wrong because in my mind I calculated 750/4 = 175. It should have been 187.5. Thus my error.

Good job!
 
Thanks. It's the first time I'm doing a frequency problem, and you've been a great help.
 
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