How Do Nodes Function in Standing Waves with Fixed and Open Ends?

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SUMMARY

This discussion clarifies the behavior of nodes in standing waves, specifically in fixed and open-ended scenarios. For a wave fixed at both ends, the fundamental frequency (1st harmonic) has 2 nodes, including the fixed endpoints. In contrast, for a wave fixed at one end and open at the other, the frequency equation f(n) = n*v / 4L indicates that "n" represents the harmonic level, not the number of nodes. Odd harmonics (n=1,3,5,7) apply in this case, resulting in one node at the fixed end and an antinode at the open end, confirming that even harmonics do not exist in this configuration.

PREREQUISITES
  • Understanding of standing waves and harmonics
  • Familiarity with wave equations, specifically f(n) = n*v / 4L
  • Knowledge of nodes and antinodes in wave mechanics
  • Basic principles of wave behavior in fixed and open-ended systems
NEXT STEPS
  • Study the concept of harmonics in fixed and open-ended pipes
  • Learn about the relationship between wavelength and frequency in standing waves
  • Explore the mathematical derivation of wave equations for different boundary conditions
  • Investigate the physical applications of standing waves in musical instruments
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Students studying physics, particularly those focusing on wave mechanics, as well as educators seeking to clarify concepts related to harmonics and standing waves.

kathyt.25
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Homework Statement


I don't have an actual problem to solve, it's more of a conceptual problem.

I'm trying to understand harmonics and standing waves, and how the nodes work out, but it's very confusing.

(1) If a wave is FIXED at both ends, for the fundamental or 1st harmonic, does it have 0 nodes, 1 node, or 2 nodes? Do you count both "end nodes" where the wave is fixed?

(2) If a wave is FIXED at one end, and OPEN at the other end, I know that the equation for frequency is f(n) = n*v / 4L, where n=1,3,5,7...
Does "n" represent the # nodes, or the harmonic level?
This is super confusing for me, because for f(1), there is 1 node at the fixed end, which makes sense, because this is the first harmonic.
However, for f(2), there are 2 nodes, but "n" can only equal odd numbers. So there is no second harmonic... Why is that? So to find values of n, we have to go by harmonic number, and not the number of nodes, for all situations (ie. open, closed, open-closed waves)?


Homework Equations





The Attempt at a Solution

 
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kathyt.25 said:
(1) If a wave is FIXED at both ends, for the fundamental or 1st harmonic, does it have 0 nodes, 1 node, or 2 nodes? Do you count both "end nodes" where the wave is fixed?
Yes you do.

kathyt.25 said:
(2) If a wave is FIXED at one end, and OPEN at the other end, I know that the equation for frequency is f(n) = n*v / 4L, where n=1,3,5,7...
Does "n" represent the # nodes, or the harmonic level?
This is super confusing for me, because for f(1), there is 1 node at the fixed end, which makes sense, because this is the first harmonic.
However, for f(2), there are 2 nodes, but "n" can only equal odd numbers. So there is no second harmonic... Why is that? So to find values of n, we have to go by harmonic number, and not the number of nodes, for all situations (ie. open, closed, open-closed waves)?
Think of it this way: n represents the number of half-wavelengths that fit into the length L. A wave that consists of an odd number of half-wavelengths has a node at one end and an antinode at the other end, which fits perfectly into a pipe that's open at one end and closed at the other. Alternatively, for a wave that has an even number of half-wavelengths, there are two possibilities: either it has a node at both ends, which fits a pipe that's closed at both ends, or it has an antinode at both ends, which fits a pipe that's open at both ends. That's why for pipes that are open at both ends or closed at both ends, n only takes even values.
 

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