How Do Proton and Electron Path Radii Compare in a Magnetic Field?

  • Thread starter Thread starter Jack16
  • Start date Start date
Click For Summary

Homework Help Overview

The discussion revolves around comparing the radii of circular paths taken by a proton and an electron when both enter a magnetic field with the same kinetic energy. The subject area includes concepts from electromagnetism and circular motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between momentum and gyroradius, and some suggest using the Lorentz force to analyze the forces acting on the particles. Others mention the need to consider circular motion dynamics and the equations governing it.

Discussion Status

The discussion is ongoing, with various approaches being explored. Some participants have provided insights into the relationships between mass, velocity, and magnetic field strength, while others question the initial assumptions and suggest alternative methods for analysis.

Contextual Notes

There is mention of using kinetic energy and the effects of a magnetic field, but the specific values or additional constraints are not provided. Participants are also navigating through the implications of different particle properties, such as mass and charge.

Jack16
Messages
13
Reaction score
0
This Is A Challenging One...

A proton and an electron have the same kinetic energyuopn entering a region of constant magnetic field
What is the ratio of the radii of their circular paths?

I used MeVe squared= MpVp squared
but i couldn't get the ratios from these...
 
Physics news on Phys.org
You need to use the fact that the gyroradius varies directly with the momentum of the particle.
 
Force due to magnetic field : F = qvB, with v perpendicular to F
Force due to circular motion : F = ? (the most elementary form...)

Mix all of this together using Newton's 3rd.
 
curved path

use the fact that in circular motion, F=(mv^2)/r.

after a bit of fiddling that gives you the ratios of the circles:

r(p) = radius for proton path
r(e) = radius of electron path
m(e) = mass of electron
m(p) = mass of proton
v = velocity of particle
B = mag field strength
V = Voltage across plates

r(e) : r(p) = - (m(e)v^2)/BV : (m(p)v^2)/BV
 
You are heading wrong way, to calculate take lorentz force in account and try it again
use relation,
(mv^2)/2 = qvb
m mass
v velocity
q charge
b magnetic field.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 16 ·
Replies
16
Views
6K
  • · Replies 25 ·
Replies
25
Views
5K
Replies
14
Views
3K
Replies
7
Views
2K
  • · Replies 0 ·
Replies
0
Views
869