How Do Pseudo Differential Operators Solve Infinite-Dimensional ODEs?

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SUMMARY

Pseudo differential operators are utilized to solve infinite-dimensional ordinary differential equations (ODEs) by employing the operator f(∂_x)y(x) = h(x). When h(x) equals zero, the ansatz y(x) = e^{ax} leads to the equation ∑_ρ e^{xρ} f(ρ) = 0. For non-zero h(x), an orthonormal basis is constructed from the solutions to express results over the interval (0, c). The discussion also explores the meaning of the expression G(x,y) = ∫ dV (e^{ik|x-y|}/(E - Ak² - V(∂_k))) and its implications in the context of pseudo differential operators.

PREREQUISITES
  • Understanding of pseudo differential operators
  • Familiarity with infinite-dimensional ODEs
  • Knowledge of orthonormal basis construction
  • Proficiency in integral calculus involving complex functions
NEXT STEPS
  • Study the properties of pseudo differential operators in detail
  • Explore the construction of orthonormal bases in functional analysis
  • Learn about the applications of infinite-dimensional ODEs in physics
  • Investigate the implications of G(x,y) in quantum mechanics and field theory
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Mathematicians, physicists, and researchers focusing on differential equations, particularly those working with infinite-dimensional systems and pseudo differential operators.

Klaus_Hoffmann
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let be the operator involving an infinite-dimensional ODE

[tex]f( \partial _{x}) y(x)=h(x)[/tex]

then if h(x)=0 i make the ansatz [tex]y(x)=e^{ax}[/tex] so

[tex]\sum_{\rho } e^{x\rho}[/tex] [tex]f(\rho) =0[/tex]

for h(x) different from '0' we construct an orthonormal basis with the solutions given above to give an expression on the interval (0,c)

Another question,.. can we give a 'meaning' to the expression.

[tex]G(x,y)= \int dV \frac{e^{ik|x-y|}{E-Ak^{2}-V(\partial _{k})}[/tex]
 
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i meant the operator

[tex]\int_{a}^{b}dx \frac{exp(-iux)}{x+f(\partial)-5}[/tex]

where the derivative is respect to 'x'
 

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