How Do Quotient Spaces in Topology Relate to Attachments and Retractions?

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Homework Help Overview

The discussion revolves around quotient spaces in topology, specifically focusing on the attachment of two spaces along a closed subset and the implications of strong deformation retracts on homotopy equivalences. The original poster presents a problem involving the relationship between these concepts and seeks clarity on the connections between the spaces involved.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand how the strong deformation retract of a space relates to the quotient space formed by attaching another space. They question the relevance of the homotopy defined on X to the quotient space X∪_fY. Another participant provides an example to illustrate the attachment concept, discussing the identification of elements and the resulting homotopy equivalence.

Discussion Status

Some participants are exploring the implications of the definitions and relationships between the spaces, with one participant expressing that they are beginning to grasp the concepts. There is an acknowledgment of the complexity involved in writing proofs in topology, indicating a shared experience of frustration with the subject.

Contextual Notes

Participants note the challenges in formulating proofs in topology, particularly regarding fundamental groups and their properties. The discussion reflects a mix of theoretical exploration and practical concerns about conveying understanding in a classroom setting.

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Let X,Y be two spaces, A a closed subset of X, f:A--->Y a continuous map. We denote by X\cup_fY the quotient space of the disjoint union X\oplus{Y} by the equivalence relation ~ generated by a ~ f(a) for all a in A. This space is called the attachment of X with Y along A via f.

i) If A is a strong deformation retract of X, show that Y is a deformation retract of X\cup_fY.

ii) The map f is extendable to a continuous map F:X-->Y if and only if Y is a retract of X\cup_fY.

I'm really stuck on this question. If A is a strong deformation retract of X, then we have some homotopy H:X\times[0,1]\rightarrowX where for all x in X, H(x,0) = x. H(x,1) is in A. and for all b in A and all t in [0,1], H(a,t) = a.

But what has that got to do with X\cup_fY?

Are the members of X\cup_fY the equivalence classes where for a~b if one of: a = b, f(a)=f(b), a is in A and b=f(u) in Y.

So we want to come up with a map \varphi:X\cup_fY\rightarrow{Y} where for all y in Y, \varphi(y) = y. :confused:
 
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Things in the attachment are things in X or Y but where we identify an element in A with its image. Example: X=Y= a disc A is the boundary of X and f is an isomorphism onto the boudary of Y. The attachment is then two discs identified along their boundary, ie a sphere.

now imagine X is a punctured disc, so it is strongly homotopic to its boundary, S^1. Then it is clear that the join along the boundary is now a punctured sphere, and that this is homotopy equivalent to the disc Y, and that this homotopy can just be taken by extending the strong homotopy of X to its boundary by making it the identity on Y.
 
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hmm thanks a lot Matt I think I've got it.
 
topology is/was for me very frustrating. the results in it are easily seen to be true but it is always hard to write down the proofs because they are so fiddly. take for instance the proof that the fundamental group is indeed a group (associativity of loops) and independent of base point (in a path connected space). try to think of an easy example. at least you will be able to desribe that so that your teachers understand you understand what is going on.
 

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