How Do SI Units Affect Calculations in Fluid Statics?

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SUMMARY

The discussion focuses on calculating pressure in fluid statics using SI units. The user correctly applied the formula P = hpg with h = 0.0125 km, p = 1000 kg/m³, and g = 9.8 m/s², resulting in a gauge pressure of 122.5 N/m². The total pressure at a depth of 12.5 m, incorporating atmospheric pressure of 101,325 Pascals, was calculated as 101,122.5 N/m². Key insights include the importance of using meters instead of kilometers for depth in pressure calculations.

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  • Understanding of fluid statics principles
  • Familiarity with SI units and conversions
  • Knowledge of pressure calculations using P = hpg
  • Basic grasp of atmospheric pressure values
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  • Learn about the implications of using different units in pressure calculations
  • Explore the relationship between pressure, depth, and fluid density
  • Investigate common mistakes in unit conversions in physics problems
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clueless8
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Homework Statement
I'm having trouble getting the correct answer on two problems within one and I don't know where I'm going wrong. I will go to my T.As during the week but I would rather finish my homework this weekend.

The question is If you were to dive down 12.5m below surface level, what is
1. The pressure due to water alone?
2.The total or absolute pressure at depth given atmospheric pressure = 1.01E5 N/m^2
Relevant Equations
P = hpg
Ptotal = Pgauge + Patm
For A) I used P = hpg (h=0.0125km, p=1000kg/m^3, and g= 9.8m/s^2) this gave me 122.5N/m^2
For B) I used Ptotal = Pgauge + Patm
= 1.01E5 + 122.5 = 101122.5 N/m^2
 
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clueless8 said:
Homework Statement: I'm having trouble getting the correct answer on two problems within one and I don't know where I'm going wrong. I will go to my T.As during the week but I would rather finish my homework this weekend.

The question is If you were to dive down 12.5m below surface level, what is
1. The pressure due to water alone?
2.The total or absolute pressure at depth given atmospheric pressure = 1.01E5 N/m^2
Relevant Equations: P = hpg
Ptotal = Pgauge + Patm

For A) I used P = hpg (h=0.0125km, p=1000kg/m^3, and g= 9.8m/s^2) this gave me 122.5N/m^2
For B) I used Ptotal = Pgauge + Patm
= 1.01E5 + 122.5 = 101122.5 N/m^2
Why did you convert to km?
 
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Welcome!

1 Pascal = Force of 1 Newton per square meter
Atmospheric pressure at sea level = 101,325 Pascals = 760 mm Hg = 760 torr = 14.7 psi = 1 atm
 
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Lnewqban said:
Welcome!

1 Pascal = Force of 1 Newton per square meter
Atmospheric pressure at sea level = 101,325 Pascals = 760 mm Hg = 760 torr = 14.7 psi = 1 atm
The valuel of atmospheric pressure to use is given.
 
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clueless8 said:
For A) I used P = hpg (h=0.0125km, p=1000kg/m^3, and g= 9.8m/s^2) this gave me 122.5N/m^2
Check your units!
 
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haruspex said:
Why did you convert to km?
I have trouble in this area, I assumed I had to due because the final answer asks for N/m^2 so I thought it had to be in km due to SI units , should I stick with 12.5m ?
 
clueless8 said:
I have trouble in this area, I assumed I had to due because the final answer asks for N/m^2 so I thought it had to be in km due to SI units , should I stick with 12.5m ?
The SI base unit of length is 1 m, not 1 km. The derived unit of newton is 1 N = 1 kg m/s2, not a km to be seen anywhere. The only ”k” in there is in kg, the SI base unit for mass.
 

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