How Do SI Units Affect Calculations in Fluid Statics?

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Homework Help Overview

The discussion revolves around fluid statics, specifically calculating pressure at a certain depth in water and understanding the implications of using SI units in these calculations.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculations for pressure due to water and total pressure at depth, questioning the conversion of depth from meters to kilometers. There are inquiries about the appropriateness of unit usage in the context of SI units.

Discussion Status

Some participants have provided calculations and relevant equations, while others are questioning the unit conversions and the necessity of using kilometers instead of meters. There is an ongoing exploration of the correct approach to the problem.

Contextual Notes

Participants note that the SI base unit of length is meters, and there is confusion regarding the conversion of depth for the calculations. The relevance of using atmospheric pressure in the calculations is also mentioned.

clueless8
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Homework Statement
I'm having trouble getting the correct answer on two problems within one and I don't know where I'm going wrong. I will go to my T.As during the week but I would rather finish my homework this weekend.

The question is If you were to dive down 12.5m below surface level, what is
1. The pressure due to water alone?
2.The total or absolute pressure at depth given atmospheric pressure = 1.01E5 N/m^2
Relevant Equations
P = hpg
Ptotal = Pgauge + Patm
For A) I used P = hpg (h=0.0125km, p=1000kg/m^3, and g= 9.8m/s^2) this gave me 122.5N/m^2
For B) I used Ptotal = Pgauge + Patm
= 1.01E5 + 122.5 = 101122.5 N/m^2
 
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clueless8 said:
Homework Statement: I'm having trouble getting the correct answer on two problems within one and I don't know where I'm going wrong. I will go to my T.As during the week but I would rather finish my homework this weekend.

The question is If you were to dive down 12.5m below surface level, what is
1. The pressure due to water alone?
2.The total or absolute pressure at depth given atmospheric pressure = 1.01E5 N/m^2
Relevant Equations: P = hpg
Ptotal = Pgauge + Patm

For A) I used P = hpg (h=0.0125km, p=1000kg/m^3, and g= 9.8m/s^2) this gave me 122.5N/m^2
For B) I used Ptotal = Pgauge + Patm
= 1.01E5 + 122.5 = 101122.5 N/m^2
Why did you convert to km?
 
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Welcome!

1 Pascal = Force of 1 Newton per square meter
Atmospheric pressure at sea level = 101,325 Pascals = 760 mm Hg = 760 torr = 14.7 psi = 1 atm
 
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Lnewqban said:
Welcome!

1 Pascal = Force of 1 Newton per square meter
Atmospheric pressure at sea level = 101,325 Pascals = 760 mm Hg = 760 torr = 14.7 psi = 1 atm
The valuel of atmospheric pressure to use is given.
 
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clueless8 said:
For A) I used P = hpg (h=0.0125km, p=1000kg/m^3, and g= 9.8m/s^2) this gave me 122.5N/m^2
Check your units!
 
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haruspex said:
Why did you convert to km?
I have trouble in this area, I assumed I had to due because the final answer asks for N/m^2 so I thought it had to be in km due to SI units , should I stick with 12.5m ?
 
clueless8 said:
I have trouble in this area, I assumed I had to due because the final answer asks for N/m^2 so I thought it had to be in km due to SI units , should I stick with 12.5m ?
The SI base unit of length is 1 m, not 1 km. The derived unit of newton is 1 N = 1 kg m/s2, not a km to be seen anywhere. The only ”k” in there is in kg, the SI base unit for mass.
 

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