Calculation of atmospheric presure

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Homework Help Overview

The discussion revolves around estimating atmospheric pressure at a height of 550 meters above sea level in London, using given values for atmospheric pressure and air density. The original poster attempts to apply the hydrostatic pressure equation while questioning the validity of assuming constant air density with height.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation method using the equation patm = rho g h and the implications of the assumption that air density remains constant. There are inquiries about the correctness of the results and the significance of figures in the final answer.

Discussion Status

The discussion is ongoing, with participants providing feedback on the calculations and raising questions about significant figures. There is no explicit consensus on the correctness of the results, but guidance regarding significant figures has been offered.

Contextual Notes

Participants note the importance of significant figures in the calculations, and there is some uncertainty regarding the expectations of the instructor related to precision.

Derek1997
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Homework Statement


Taking atmospheric pressure at sea level to be 1x10^5 pa CPa and the density of air at sea level to be
about 1.2kg/m^3,estimate the atmospheric pressure in London 550m above sea level. For this calculation, it is easiest to assume that air density doesn’t change with height – briefly discuss
the validity of this assumption

Homework Equations


patm= rho g h

The Attempt at a Solution


Well, I did p=pgh- 1.2x9.8x550 and substracted the answer by the atmosperhic pressure of the sea to get the answer? Am I right?
 
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Derek1997 said:
Am I right?
Don't know, you haven't stated your result. It's certainly one way to "estimate" atmospheric pressure in London.
 
Bystander said:
Don't know, you haven't stated your result. It's certainly one way to "estimate" atmospheric pressure in London.
Well alright thanks for reply.. here the results i got above
so for p atmospheric i got- 1.2kg/m^3x9.8m/s^2x 550m= 6648pa then i substractfrom the very given pressure that is 1x10^5pa-6648pa= 93352pa pressure of london?
 
Derek1997 said:
1x10^5pa-6648pa= 93352pa pressure of london?
You might want, in addition, to pay attention to significant figures.
 
Bystander said:
You might want, in addition, to pay attention to significant figures.
you mean i convert to kpa?
 
Bystander said:
to significant figures.
Not units --- significant figures.
 
I don't understand. 93352pa= 92.5kpa?
 
Yes. I'll re-emphasize the "might," I've no idea how picky your instructor "might" be.
 
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Oh ok, thanks i gave u a like.
 
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  • #10
:wink:
 

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